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3 years ago

A falling object accerlates from -10.0m/s to -30.0m/s how much time does that take

Mathematics

1 answer:

Leya [2.2K]3 years ago

5 0

Answer:

2.04 seconds

Step-by-step explanation:

Falling objects near the surface of the earth have an acceleration of -9.81 m/s².

Acceleration is the change in velocity over change in time:

a = (v − v₀) / t

-9.81 = (-30.0 − (-10.0)) / t

-9.81 = -20.0 / t

t = 2.04

It takes 2.04 seconds.

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If you could show as much work as possible that would be amazing!!

Nikitich [7]

Answers:

Reduce:

Here we gave to simplify the expressions:

9) $x^{2}+7x+\frac{12}{x^{2}}+11x+28$

Grouping similar terms:

$(x^{2}+\frac{12}{x^{2}})+(18x+28)$

Applying common factor $x^{2}$ in the first parenthesis and common factor $2$ in the second parenthesis:

$x^{2}(1+\frac{12}{x^{4}})+2(9x+14)$ This is the answer

11) $y^{3}+\frac{27}{y^{2}}+2y-3$

Rearranging the terms:

$(y^{3}+2y)+(\frac{27}{y^{2}}-3)$

Applying common factor $y$ in the first parenthesis and common factor $3$ in the second parenthesis:

$y(y^{2}+2)+3(\frac{9}{y^{2}}-1)$ This is the answer

Multiply:

19) $(\frac{12a^{9}u^{7}}{15 c})(\frac{3c^{4}}{21a^{13 u^{8}}})$

Multiplying both fractions:

$\frac{36 a^{9}u^{7}c^{4}}{315 c a^{13}u^{8}}$

Dividing numerator and denominator by 3 and simplifying:

$\frac{12 c^{3}}{105 c a^{4}u}$ This is the answer

21) $(x-\frac{3}{x}-7)(x^{2}-9x+\frac{35}{x^{2}}-18)$

$(\frac{x^{2}-3-7x}{x})(\frac{x^{4}-9x^{3}+35-18x^{2}}{x^{2}})$

Operating with cross product:

$x^{2} (x^{2}-3-7x) x(x^{4}-9x^{3}+35-18x^{2})$

$x^{9} -9x^{8} -18x^{7}+35x^{5}-7x^{8} +63x^{7}+126x^{6}-245x^{4}-3x^{7}+27x^{6}+54x^{5}-105x^{3}$

Grouping similar terms and factoring:

$x^{9}-2(8x^{8}+21x^{7} )+153x^{6}+89x^{5}-5(49x^{4}+21x^{3})$ This is the answer

Divide:

29) $\frac{\frac{k^{6}}{x^{2}}}{\frac{2k^{4}}{3x^{6}}}$

$\frac{3k^{6}x^{6}}{2x^{2}k^{4}}$

Simplifying:

$\frac{3}{2} k^{2}x^{4}$ This is the answer

33) $\frac{\frac{x+5}{x+1}}{\frac{x^{2}+11x+30}{x^{2}+3x+2}}$

$\frac{(x+5)(x^{2}+3x+2)}{(x+1)(x^{2}+11x+30)}$

Factoring numerator and denominator:

$\frac{(x+5)(x+2)(x+1)}{(x+1)(x+6)(x+5)}$

Simplifying:

$\frac{x+2}{x+6}$ This is the answer

37) $\frac{\frac{x-10}{x+13}}{\frac{x^{3}-1000}{x^{2}+15x+21}}$

$\frac{(x-10)(x^{2}+15x+21)}{(x+13)(x^{3}-1000)}$

Applying the distributive property in numerator and denominator:

$\frac{x^{3}+15x^{2}+21x-10x^{2}-150x-210}{(x+13)(x^{4}-1000x+13x^{3}-13000)}$

Grouping similar terms and factoring by common factor:

$-\frac{5x(x^{2}-129)(x^{2}-42)}{1000x^{3} (x+13)(x-13)}$

Dividing by $5$ in numerator and denominator and simplifying:

$-\frac{(x^{2}-129)(x^{2}-42)}{200x^{2}(x+13)(x-13)}$ This is the answer

3 0

3 years ago

If ac =x+3 and db=3x-19, find ac

AveGali [126]

We need some sort of diagram to see what they are. Is there any way to say that ac = db? Either equal angles or equal lines.
x + 3 = 3x - 19 Add 19
x + 3 + 19 = 3x Subtract x
21 = 2x
x = 21 / 2
x = 10.5

ac = 10.5 + 3
x = 13.5

7 0

3 years ago

Which statement about 3 multiplied by 23 must be true?

kumpel [21]

Answer:

Step-by-step explanation:

you make 3 groups of 23 and u get 69

its greater then 23 and 4

and its not between 3 and 4 or between 23 or 3

so it can only be (C)

9 0

2 years ago

Find the complex fourth roots of 81(cos(3pi/8) + i sin(3pi/8))

BartSMP [9]

By using De Moivre's theorem:

If we have the complex number ⇒ z = a ( cos θ + i sin θ)
∴ $\sqrt[n]{z} = \sqrt[n]{a} \ (cos \ \frac{\theta + 360K}{n} + i \ sin \ \frac{\theta +360k}{n} )$
k= 0, 1 , 2, ..... , (n-1)

For The given complex number ⇒ z = 81(cos(3π/8) + i sin(3π/8))


Part (A) find the modulus for all of the fourth roots

∴ The modulus of the given complex number = l z l = 81

∴ The modulus of the fourth root = $\sqrt[4]{z} = \sqrt[4]{81} = 3$

Part (b) find the angle for each of the four roots

The angle of the given complex number = $\frac{3 \pi}{8}$
There is four roots and the angle between each root = $\frac{2 \pi}{4} = \frac{\pi}{2}$
The angle of the first root = $\frac{ \frac{3 \pi}{8} }{4} = \frac{3 \pi}{32}$
The angle of the second root = $\frac{3\pi}{32} + \frac{\pi}{2} = \frac{19\pi}{32}$
The angle of the third root = $\frac{19\pi}{32} + \frac{\pi}{2} = \frac{35\pi}{32}$
The angle of the fourth root = $\frac{35\pi}{32} + \frac{\pi}{2} = \frac{51\pi}{32}$

Part (C): find all of the fourth roots of this

The first root = $z_{1} = 3 ( cos \ \frac{3\pi}{32} + i \ sin \ \frac{3\pi}{32})$
The second root = $z_{2} = 3 ( cos \ \frac{19\pi}{32} + i \ sin \ \frac{19\pi}{32})$

The third root = $z_{3} = 3 ( cos \ \frac{35\pi}{32} + i \ sin \ \frac{35\pi}{32})$
The fourth root = $z_{4} = 3 ( cos \ \frac{51\pi}{32} + i \ sin \ \frac{51\pi}{32})$

7 0

3 years ago

Given the inequality n <-12 or n 2 -10, which of the following would NOT be a solution to this inequality?

borishaifa [10]

A is the correct answer

7 0

3 years ago