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timurjin [86]
4 years ago
12

During the time interval 0 Less than or equal to t less than or equal to 4.5, water flows into tank A at rate of a(t) = (2t-5) +

5e^(2sint) During same time interval water flows into tank B at a rate of B(t) litters per ours both tanks are empty at t = 0 graphs intersect at .892 and 2.416
During time interval 0 less than or equal to t less than or equal to k water flows into tank B at a constant rate of 20.5 litters per hour what is the difference between the amount of water in tank A and the amount of water in tank b at time t = k
Mathematics
1 answer:
ololo11 [35]4 years ago
3 0

Answer:

Photomath

Step-by-step explanation:

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raketka [301]

Answer:

50

Step-by-step explanation:

4 0
3 years ago
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Harry's mother makes cakes for a local resturant. She buys flour and sugar in large amounts. She has 157.86 pounds of flour and
dolphi86 [110]
Should last up to 10 days for both
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3 years ago
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The sum of -3 and 12 increased by 5
aev [14]
-3+12+5=
-3+14=
17-3=14


The answer is 14.

First combine 12 and 5 to get 17. Then take the sign of the bigger number which is positive. Then subtract the bigger number from the smaller number to get 14z
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3 years ago
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Can someone please help me solve the problem
Marrrta [24]

Given:

The exponential function is:

y=630(0.94)^x

To find:

The percentage rate of increase or decrease.

Solution:

The general exponential function is:

y=a(1+r)^x           ...(i)

Where, a is the initial value, |r| is the growth rate in decimals if r>0 and |r| is the decay rate in decimal if r<0.

The exponential function is:

y=630(0.94)^x

It can be written as:

y=630(1-0.06)^x

y=630(1+(-0.06))^x        ...(ii)

On comparing (i) and (ii), we get

r=-0.06

Since r is negative, therefore the given function is a decreasing or decay function.

Now,

|r|=|-0.06|

|r|=0.06

So, the rate of decrease is 0.06. Multiply this number by 100 to get the percentage.

0.06\times 100=6\%

Therefore, the rate of decrease is 6%.

8 0
3 years ago
The table below shows the function f. x 1 2 3 4 5 f(x) -63 -44 ? -6 13 Determine the value of f(3) that will lead to an average
Elina [12.6K]

Answer:

C. -25

Step-by-step explanation:

x 1 2 3 4 5

f(x) -63  -44 ? -6 13

Rate of change : (-44 + 63)/(2 - 1) = 19

so

-63 + 19 = -44

- 44 + 19 = -25

- 25 + 19 = -6

- 6 + 19 = 13

Answer: f(3) = -25

7 0
3 years ago
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