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timurjin [86]
3 years ago
12

During the time interval 0 Less than or equal to t less than or equal to 4.5, water flows into tank A at rate of a(t) = (2t-5) +

5e^(2sint) During same time interval water flows into tank B at a rate of B(t) litters per ours both tanks are empty at t = 0 graphs intersect at .892 and 2.416
During time interval 0 less than or equal to t less than or equal to k water flows into tank B at a constant rate of 20.5 litters per hour what is the difference between the amount of water in tank A and the amount of water in tank b at time t = k
Mathematics
1 answer:
ololo11 [35]3 years ago
3 0

Answer:

Photomath

Step-by-step explanation:

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Find the midpoint of the segment with the following end points (10,5) and (6,9)
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Step-by-step explanation:

Let (x, y) be the mid-point

Given the points

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Using the formula to find the mid-point between the endpoints (10,5) and (6,9)

\left(x,\:y\right)=\left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)

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