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timurjin [86]
4 years ago
12

During the time interval 0 Less than or equal to t less than or equal to 4.5, water flows into tank A at rate of a(t) = (2t-5) +

5e^(2sint) During same time interval water flows into tank B at a rate of B(t) litters per ours both tanks are empty at t = 0 graphs intersect at .892 and 2.416
During time interval 0 less than or equal to t less than or equal to k water flows into tank B at a constant rate of 20.5 litters per hour what is the difference between the amount of water in tank A and the amount of water in tank b at time t = k
Mathematics
1 answer:
ololo11 [35]4 years ago
3 0

Answer:

Photomath

Step-by-step explanation:

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Dilations… please help I will give you brainless
DochEvi [55]

Answer:

The scale factor is 0.5

Step-by-step explanation:

Divide.

2/1=2

4/2=2

4/2=2

8/4=2

2/1=2

5/1.25=2

Now then, since this is a shrinking factor, divide 1 by the common outcome from the last section (2) to get 0.5

4 0
3 years ago
Find the x and y-intercepts of the line whose equation is 3x+ 5y=-15
xenn [34]
X - Intercept:    3x + 5y = -15
                      3x + 5(0) = -15
                          3x + 0 = -15
                                3x = -15
                                 3       3
                                  x = -5
                            (x, y) = (-5, 0)

Y - Intercept:     3x + 5y = -15
                       3(0) + 5y = -15
                           0 + 5y = -15
                                 5y = -15
                                  5       5
                                   y = -3
                             (x, y) = (0, -3)
6 0
3 years ago
Please Help Me???
Lemur [1.5K]
The answer should be y= -1/4-2
6 0
2 years ago
Read 2 more answers
HELP ASAP, PLEASE!!!!
GalinKa [24]

Using the t-distribution, as we have the standard deviation for the sample, we have that the test statistic is given by:

t = \frac{-20 - 0}{\sqrt{\frac{32.66}{7}}}

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is no difference, that is:

H_0: \mu = 0

At the alternative hypothesis, it is tested if there is a difference, that is:

H_1: \mu \neq 0

<h3>What is the test statistic?</h3>

The test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • s is the standard deviation of the sample.
  • n is the sample size.

In this problem, \mu = 0 is tested at the null hypothesis, and the sample is: 20, -40, -40, 0, 20, - 60, -40, hence:

\overline{x} = -20, s = \sqrt{32.66}, n = 7.

Hence, the test statistic is:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{-20 - 0}{\frac{\sqrt{32.66}}{\sqrt{7}}}

t = \frac{-20 - 0}{\sqrt{\frac{32.66}{7}}}

More can be learned about the t-distribution at brainly.com/question/16313918

5 0
3 years ago
Please help i need help ASAP!!!!!!!!!!!!!!!!!!!!!!!!!
liberstina [14]
If you suposed to do 141.3 -pie then i got d but i kinda confused.. so it might be D .....
7 0
3 years ago
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