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timurjin [86]
3 years ago
12

During the time interval 0 Less than or equal to t less than or equal to 4.5, water flows into tank A at rate of a(t) = (2t-5) +

5e^(2sint) During same time interval water flows into tank B at a rate of B(t) litters per ours both tanks are empty at t = 0 graphs intersect at .892 and 2.416
During time interval 0 less than or equal to t less than or equal to k water flows into tank B at a constant rate of 20.5 litters per hour what is the difference between the amount of water in tank A and the amount of water in tank b at time t = k
Mathematics
1 answer:
ololo11 [35]3 years ago
3 0

Answer:

Photomath

Step-by-step explanation:

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Step-by-step explanation:

2 + 2 = 4

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What is the distance between (-3,2) and (3,0)
KATRIN_1 [288]

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right 6 and down 2

Step-by-step explanation:

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The question is: "Without actually graphing, describe how the graph of y = ( -2^(x+17) ) - 4.3 is related to the graph of y = 2^
Leokris [45]

Answer:

The function has been flipped due to the negative in front.

The function has been shifted 17 units to the left.

The function has been shifted 4.3 units down.

Step-by-step explanation:

When functions are transformed there are a few simple rules:


  • Adding/subtracting inside the parenthesis to the input shifts the function left(+) and right(-).
  • Adding/subtracting outside the parenthesis to the output shifts the function up(+) and down(-).
  • Multiplying the function by a number less than 1 compresses it towards the x-axis.
  • Multiplying the function by a number greater than 1 stretches it away from the x-axis.
  • Multiplying by a negative flips the graph.

The graph of (-2^{x+17}) -4.3 compares to 2^x in the following ways:

The function has been flipped due to the negative in front.

The function has been shifted 17 units to the left.

The function has been shifted 4.3 units down.

4 0
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