The coordinates of the pre-image of point F' is (-2, 4)
<h3>How to determine the coordinates of the pre-image of point F'?</h3>
On the given graph, the location of point F' is given as:
F' = (4, -2)
The rule of reflection is given as
Reflection across line y = x
Mathematically, this is represented as
(x, y) = (y, x)
So, we have
F = (-2, 4)
Hence, the coordinates of the pre-image of point F' is (-2, 4)
Read more about transformation at:
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F(x)=IxI-5
when you shift it up, add the units to the end of y=IxI
when you shift it down, subtract the units to the end of y=IxI
Answer:
125x³ − 150x²y + 60xy² − 8y³
Step-by-step explanation:
(5x − 2y)³
₃C₀ (5x)³ (-2y)⁰ + ₃C₁ (5x)² (-2y)¹ + ₃C₂ (5x)¹ (-2y)² + ₃C₃ (5x)⁰ (-2y)³
(1) (125x³) (1) + (3) (25x²) (-2y) + (3) (5x) (4y²) + (1) (1) (-8y³)
125x³ − 150x²y + 60xy² − 8y³
Answer:
The range is the set of all second elements of ordered pairs (y-coordinates). Only the elements "used" by the relation or function constitute the range. Domain: all x-values that are to be used (independent values).
Step-by-step explanation:
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Answer:
(Option 2) y= x+ 4
Step-by-step explanation:
Please see attached picture for full solution.
To find equation of a line, you need to find the gradient, which is represented by m, and then substitute a coordinate.
