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LenaWriter [7]
4 years ago
9

A bag contains green tokens and black tokens. There are 36 green tokens in the bag. The ratio of green tokens to black tokens is

3 for every 4. Find the number of black tokens in the bag
Mathematics
2 answers:
erik [133]4 years ago
6 0

Answer:

48

Step-by-step explanation:

G:B   Total

3:4        7

36 divided by 3 is 12.

12 x 4 = 48

In total there are 84 tokens in the bag, 48 of which are black and 36 are green.

solong [7]4 years ago
3 0

Answer:

48

Step-by-step explanation:

We are given that

Total number of green  tokens in the bag=36

Ratio of green tokens to black tokens=3:4

We have to find the number of black tokens in the bag.

Let x be the number of black tokens in the bag.

According to question

36:x=3:4

\frac{36}{x}=\frac{3}{4}

By cross multiply , then we get

144=3x

x=\frac{144}{3}=48

By division property of equality

Hence, the number of blacken tokens in the bag=48

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Step-by-step explanation:

Step 1:

The given figure is made up of three rectangles and two triangles.

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The geometric shape's surface area = The sum of the individual surface areas.

Step 2:

The surface area of the rectangles is the multiplication of its length and width.

The surface area of the rectangle with length z and width x = (26)(10)= 260 cm^{2}.

The surface area of the rectangle with length y and width x = (24)(10)= 240 cm^{2}.

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The area of a triangle is half the product of its base length and height.

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What ratios are equivalent to 12:3
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16. From past experience, a company has found that in cartons of transistors, 92% contain no defective transistors, 3% contain o
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Answer:

E(x)=0.15

V(x)=0.3075

S(x)=0.5545

Step-by-step explanation:

The mean of a discrete variable is calculated as:

E(x)=x_1*p(x_1)+x_2*p(x_2)+...+x_n*p(n)

where x_1,x_2,...,x_n are the values that the variable can take and p(x_1),p(x_2),...,p(x_n) are their respective probabilities.

So, if we call x the number of defective transistors in cartons, we can calculate the mean E(x) as:

E(x)=(0*0.92)+(1*0.03)+(2*0.03)+(3*0.02)=0.15

Because there are 0 defective transistor with a probability of 0.92, 1 defective transistor with a probability of 0.03, 2 defective transistors with a probability of 0.03 and 3 defective transistors with a probability of 0.01.

At the same way, the variance V(x) is calculated as:

V(x)=E(x^2)-(E(x))^2

Where E(x^2)=x_1^2*p(x_1)+x_2^2*p(x_2)+...+x_n^2*p(n)

So, the variance V(x) is equal to:

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Finally, the standard deviation is calculated as:

S(x)=\sqrt{V(x)} \\S(x)=\sqrt{0.3075} \\S(x)=0.5545

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