For this case we must indicate the inequality represented in the graph.
It is noted that we have a closed point at -1, so the inequality at that point contains equality and is represented by "[". On the other hand, we observe an open point at +3, so inequality does not include equality (does not include +3) and is represented as ")".
So, the interval of the graph is:
This is equivalent to:
Answer:
Option B
Answer:
Step-by-step explanation:
To find the volume of this solid, multiply the base area by the height:
V = (25 cm²)(4 cm) = 100 cm³
Answer:
27.2 ft
Step-by-step explanation:
Let's set up a ratio that represents the problem:
Object's Height (ft) : Shadow (ft)
Substitute with the dimensions of the 34 foot pole and its 30 foot shadow.
34 : 30
Find the unit rate:
The unit rate is when one number in a ratio is 1.
Let's make the Shadow equal to one by dividing by 30 on both sides.
Object's Height (ft) : Shadow (ft)
34 : 30
/30 /30
1.13 : 1
Now, let's multiply by 24 on both sides to find the height of the tree.
Multiply:
Object's Height (ft) : Shadow (ft)
1.13 : 1
x24 x24
27.2 : 24
Therefore, the tree is 27.2 feet tall.
Answer:
Step-by-step explanation:
We can rewrite the equation as
Notice that we have 
in both the numerator and the denominator, so it looks like we can divide it out. However, what if is 
? Then we would have 
, which is undefined. So although it looks like the numerator and denominator can be simplified, the resulting function we would get from simplification would not have the same behavior as this one (since such a function would be defined for 
, but this one is not).
A point of discontinuity refers to a particular point which is included in the simplified function, but which is not included in the original one. In this case, the point which is not included in the unsimplified function is at . In the simplified version of the function, if we plug in , we get
So the point is our only point of discontinuity.
It's also important to distinguish between specific points of discontinuity and vertical asymptotes. This function also has a vertical asymptote at 
(since it causes the denominator to be 0), but the difference in behavior is that in the case of the asymptote, only the denominator becomes 0 for a specific value of 
