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bixtya [17]
3 years ago
8

Pete has 5 marbles . Jay has a number of marbles that is two more than 5 . How many marbles does jay have?

Mathematics
2 answers:
Sliva [168]3 years ago
8 0

Answer:

The answer is 7

Step-by-step explanation:

kogti [31]3 years ago
5 0

Answer:

7 marbles

Step-by-step explanation:

You would put five first because that's how much marbles pete had and for jay you just add a 2.

5+2=7

Hope this helps:)

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Choose the slope-intecept form of the equation of the line through the given points.
DerKrebs [107]

Answer:

B

Step-by-step explanation:

6 0
2 years ago
Point A is located at (3,-6) and point A is located at (1-2). What is the scale factor?
Anuta_ua [19.1K]

Answer:

The scale factor is 3.

Step-by-step explanation:

Let the origin O(0,0) is the reference point and the coordinates of the point A are given by (3,-6).

Therefore, the distance OA is given by \sqrt{(3 - 0)^{2} + (- 6 - 0)^{2}} = 3\sqrt{5} units.

Again, the coordinates of point A' are (1,-2).

Therefore, the distance OA' is given by \sqrt{(1 - 0)^{2} + (- 2 - 0)^{2}} = \sqrt{5} units.

Hence, the scale factor is \frac{OA}{OA'} = \frac{3\sqrt{5} }{\sqrt{5}} = 3. (Answer)

4 0
3 years ago
Express 3 to the powermof -2 as rational number
faltersainse [42]

Answer:

(2/3)³

2³/3³

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Step-by-step explanation:

3 0
3 years ago
Solve 2 log3 x + log3 5 =125​
zepelin [54]

Answer:

x = √(3^125/ 5)

approx 2.9552445 * 10^29.

Step-by-step explanation:

2 log3 x + log3 5 =125​

log3 x^2 + log3 5 = 125

log3 (5x^2) = 125

3^125 = 5x^2

x^2 = 3^125/ 5

x = √(3^125/ 5)

This is a huge number

An approximation of it is 2.9552445 * 10^29.

3 0
3 years ago
Assume that a sample is used to estimate a population proportion μ . Find the margin of error M.E. that corresponds to a sample
hichkok12 [17]

Answer:

MoE = 1.645\cdot \frac{13.1}{\sqrt{772} } \\\\MoE = 1.645\cdot 0.47147\\\\MoE = 0.776\\\\

Step-by-step explanation:

Since the sample size is quite large, we can use the z-distribution.

The margin of error is  given by

$ MoE = z_{\alpha/2}(\frac{s}{\sqrt{n} } ) $

Where n is the sample size, s is the sample standard deviation and z_{\alpha/2} is the z-score corresponding to a 90% confidence level.

The z-score corresponding to a 90% confidence level is

Significance level = α = 1 - 0.90= 0.10/2 = 0.05

From the z-table at α = 0.05

z-score = 1.645

MoE = 1.645\cdot \frac{13.1}{\sqrt{772} } \\\\MoE = 1.645\cdot 0.47147\\\\MoE = 0.776\\\\

Therefore, the margin of error is 0.776.

3 0
3 years ago
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