2 years ago

For what value of x does 4 superscript x baseline = (one-eighth) superscript x 5?

Mathematics

1 answer:

Fittoniya [83]2 years ago

6 0

An equation is formed of two equal expressions. The value of x for which 4ˣ=(1/8)ˣ⁺⁵ is 3.

<h3>What is an equation?</h3>

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

The value of x for which 4ˣ=(1/8)ˣ⁺⁵ is,

4ˣ=(1/8)ˣ⁺⁵

(2²)ˣ = (2⁻³)ˣ⁺⁵

2²ˣ = 2⁽⁻³ˣ⁺¹⁵⁾

2x = -3x + 15

5x = 15

x = 3

Hence, the value of x for which 4ˣ=(1/8)ˣ⁺⁵ is 3.

Learn more about Equation:

brainly.com/question/2263981

#SPJ1

You might be interested in

Write a multiplication problem in which the product is between 0.05 and 0.75

Sever21 [200]

.09 times 6 is .54, I hope this helps

8 0

3 years ago

Read 2 more answers

Whoever answers first gets the brainliest Given: f(x)=|x|-3 What direction does the graph move ?______ How far?______

Y_Kistochka [10]

Answer:

3 units down

Step-by-step explanation:

Compared to

f(x) = |x|,

f(x) = |x| - 3 moves 3 units down.

6 0

3 years ago

It is solving multi-step inequalities.

kati45 [8]

If you took a better picture I would be able to solve it. Sorry it is pretty blury

3 0

3 years ago

Read 2 more answers

Which is the value of this expression when p=3 and q=-9?

Ivan

Your answer is C . good luck.

3 0

3 years ago

E xex2 + y2 + z2 dv, where e is the portion of the unit ball x2 + y2 + z2 ≤ 1 that lies in the first octant.

Jlenok [28]

$\displaystyle\iiint_{\mathcal E}xe^{x^2+y^2+z^2}\,\mathrm dV$
$=\displaystyle\int_{\varphi=0}^{\varphi=\pi/2}\int_{\theta=0}^{\theta=\pi/2}\int_{\rho=0}^{\rho=1}\rho\cos\theta\sin\varphi e^{\rho^2}\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi$
$=\displaystyle\left(\int_{\rho=0}^{\rho=1}\rho^3e^{\rho^2}\,\mathrm d\rho\right)\left(\int_{\theta=0}^{\theta=\pi/2}\cos\theta\,\mathrm d\theta\right)\left(\int_{\varphi=0}^{\varphi=\pi/2}\sin^2\varphi\,\mathrm d\varphi\right)=\frac\pi8$

7 0

3 years ago