I beilieve its 3:1. I am not completely sure though
Answer:
equation of circle is (x+5)^2+(y-3)^2=16
Step-by-step explanation:
equation of circle ](https://tex.z-dn.net/?f=%28x-x_1%29%5E2%2B%28y-y_1%29%5E2%3Dr%5E2%3C%2Fp%3E%3Cp%3Ewhere%20r%3Dredius%20of%20circle%2C%5Btex%5D%28x_1%2Cy_1%29)
is centre of circle
centre of circle=(-5,3)
put the value of centre and redius in the equation
equation of circle 
=4^2
given that
c = 15h + 245
when h = 30.35 , cost c = (15 × 30.35) + 245
= 453.75 + 245 = 698.75
so cost if painter works = 698.75 unit of currency.
<span>Sphere: (x - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100
Intersection in xy-plane: (x - 4)^2 + (y + 12)^2 = 36
Intersection in xz-plane: DNE
Intersection in yz-plane: (y + 12)^2 + (z - 8)^2 = 84
The desired equation is quite simple. Let's first create an equation for the sphere centered at the origin:
x^2 + y^2 + z^2 = 10^2
Now let's translate that sphere to the desired center (4, -12, 8). To do that, just subtract the center coordinate from the x, y, and z variables. So
(x - 4)^2 + (y - -12)^2 + (z - 8)^2 = 10^2
(x - 4)^2 + (y - -12)^2 + (z - 8)^2 = 100
Might as well deal with that double negative for y, so
(x - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100
And we have the desired equation.
Now for dealing with the coordinate planes. Basically, for each coordinate plane, simply set the coordinate value to 0 for the axis that's not in the desired plane. So for the xy-plane, set the z value to 0 and simplify. So let's do that for each plane:
xy-plane:
(x - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100
(x - 4)^2 + (y + 12)^2 + (0 - 8)^2 = 100
(x - 4)^2 + (y + 12)^2 + (-8)^2 = 100
(x - 4)^2 + (y + 12)^2 + 64 = 100
(x - 4)^2 + (y + 12)^2 = 36
xz-plane:
(x - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100
(x - 4)^2 + (0 + 12)^2 + (z - 8)^2 = 100
(x - 4)^2 + 12^2 + (z - 8)^2 = 100
(x - 4)^2 + 144 + (z - 8)^2 = 100
(x - 4)^2 + (z - 8)^2 = -44
And since there's no possible way to ever get a sum of 2 squares to be equal to a negative number, the answer to this intersection is DNE. This shouldn't be a surprise since the center point is 12 units from this plane and the sphere has a radius of only 10 units.
yz-plane:
(x - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100
(0 - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100
(-4)^2 + (y + 12)^2 + (z - 8)^2 = 100
16 + (y + 12)^2 + (z - 8)^2 = 100
(y + 12)^2 + (z - 8)^2 = 84</span>
Answer:
A = 1.0 L
B = 0.50 atm
C = 0.60 atm
D = 4.0 L
Step-by-step explanation:
According to the Boyle's law, the volume of a gas is inversely proportional to its volume. If we consider an initial state (1) and a final state (2):
P₁ × V₁ = P₂ × V₂
A
P₁ × V₁ = P₂ × V₂
1.5 atm × 2.0 L = 3.0 atm × A
A = 1.0 L
B
P₁ × V₁ = P₂ × V₂
1.5 atm × 2.0 L = B × 6.0 L
B = 0.50 atm
C
P₁ × V₁ = P₂ × V₂
1.5 atm × 2.0 L = C × 5.0 L
C = 0.60 atm
D
P₁ × V₁ = P₂ × V₂
1.5 atm × 2.0 L = 0.75 atm × D
D = 4.0 L
