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kirza4 [7]
3 years ago
13

HELP PLEASE SO FAST I need thiss

Mathematics
2 answers:
dimulka [17.4K]3 years ago
8 0

The midpoint would be (-2, -1)

enot [183]3 years ago
8 0
It’s -2 -1 why do I need 20 characters
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Fanning + medal
lubasha [3.4K]
The Greatest Common Factor of the given expression should be that expression that can divide both. First, factor both expression,
           x^4 = (x³)(x)      and x³ = (x³)(1)
Therefore, both can be factored by x³. The answer is the third choice. 
7 0
3 years ago
Read 2 more answers
A random sample of 10 parking meters in a resort community showed the following incomes for a day. Assume the incomes are normal
GenaCL600 [577]

Answer:

A 95% confidence interval for the true mean is [$3.39, $6.01].

Step-by-step explanation:

We are given that a random sample of 10 parking meters in a resort community showed the following incomes for a day;

Incomes (X): $3.60, $4.50, $2.80, $6.30, $2.60, $5.20, $6.75, $4.25, $8.00, $3.00.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                         P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean income = \frac{\sum X}{n} = $4.70

            s = sample standard deviation = \sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }  = $1.83

            n = sample of parking meters = 10

            \mu = population mean

<em>Here for constructing a 95% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.</em>

<u>So, 95% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-2.262 < t_9 < 2.262) = 0.95  {As the critical value of t at 9 degrees of

                                            freedom are -2.262 & 2.262 with P = 2.5%}  

P(-2.262 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.262) = 0.95

P( -2.262 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu < 2.262 \times {\frac{s}{\sqrt{n} } } ) = 0.95

P( \bar X-2.262 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.262 \times {\frac{s}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X-2.262 \times {\frac{s}{\sqrt{n} } } , \bar X+2.262 \times {\frac{s}{\sqrt{n} } } ]

                                         = [ 4.70-2.262 \times {\frac{1.83}{\sqrt{10} } } , 4.70+ 2.262 \times {\frac{1.83}{\sqrt{10} } } ]

                                         = [$3.39, $6.01]

Therefore, a 95% confidence interval for the true mean is [$3.39, $6.01].

The interpretation of the above result is that we are 95% confident that the true mean will lie between incomes of $3.39 and $6.01.

Also, the margin of error  =  2.262 \times {\frac{s}{\sqrt{n} } }

                                          =  2.262 \times {\frac{1.83}{\sqrt{10} } }  = <u>1.31</u>

4 0
3 years ago
POSSIBLE POINTS
Mamont248 [21]

Answer:

The answer is 131 people

Step-by-step explanation:

I'm not too sure about equations bc its been a min since I've done them but maybeeeee it's 26x - (1,575) = 5,000 something like that LOL

All I know is that you have to subtract 1575 from 5,000 and then you get 3,435 dollars left and you divide that by 26 people and you get 131.731 but of course you can't have a half of person so it stays at 131.

Hopefully that helped lol

5 0
2 years ago
((write an equation using y=mx+b format))
butalik [34]

Answer: y = 2x + 5

Step-by-step explanation:

8 0
3 years ago
Jason wants to receive monthly payments of $3,250 for 15 years. How much does he have to invest now in an annuity that has an an
LuckyWell [14K]

The amount she should invest today in the annuity is $455,450.40.

<h3>How much should be invested today?</h3>

The first step is to determine the future value of the monthly annuity.

Future value = monthly payment x annuity factor

Annuity factor = {[(1+r)^n] - 1} / r

Where:

  • r = interest rate = 3.6/12 = 0.3%
  • n = number of periods : 15 x 12 = 180

Future value : 3250 x [(1.003^180) - 1] / 0.003 = 774,171.92

The second step is to determine the present value of this future annuity:

774, 171.92 / (1.036^15) = $455,450.40

To learn more about annuities, please check: brainly.com/question/24108530

#SPJ1

8 0
1 year ago
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