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3 years ago

7

A. Graph A B. Graph B C. Graph D. Graph D

1 answer:

igomit [66]3 years ago

3 0

Answer:

C

Step-by-step explanation:

y = (x-1) (x+4)

when y=0

x=1 and x= -4

so select C

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I need you to help me solve this

Svet_ta [14]

For the expression to be factor-able the Discriminant , has to be greater or equal to zero
ax^2 + cx + b = 0

c^2 - 4 ab >= 0

(-3)^2 - 4 * 1 * b >= 0

9 - 4b >= 0

9 >= 4b

b <= 9/4 (2.25)

Pick any value in that range for ex:

0 , 2, -3, -6

7 0

3 years ago

the width of the rectangle is 5 inches less than it's length, and the area is 84 square inches. what are the length and width of

inysia [295]

W= l - 5 where w = width and l = length

area = 84 = l*w = l(l-5)

l(l-5) = 84
l^2 - 5l - 84 = 0
(l - 12)(l + 7) = 0
l = 12

length = 12 and width = 7

7 0

3 years ago

Which rational number could be graphed between -3 and -4

Snezhnost [94]

Answer:

-3.5

Step-by-step explanation:

An example is -3.5.

3 0

3 years ago

Read 2 more answers

I’m soooo confused someone please helppppp!!

Ganezh [65]

Answer:

m>-5

Why? because the arrow shows -5 less then any number going right

Hope this helps

7 0

2 years ago

A movie theater has a seating capacity of 329. The theater charges $5.00 for children, $7.00 for students, and $12.00 of adults.

kipiarov [429]

Answer:

170 children

74 students

85 adults

Step-by-step explanation:

Given

Let:

$C = Children; S = Students; A = Adults$

For the capacity, we have:

$C + S + A = 329$

For the tickets sold, we have:

$5C + 7S + 12A = 2388$

Half as many as adults are children implies that:

$A = \frac{C}{2}$

Required

Solve for A, C and S

The equations to solve are:

$C + S + A = 329$ -- (1)

$5C + 7S + 12A = 2388$ -- (2)

$A = \frac{C}{2}$ -- (3)

Make C the subject in (3)

$C = 2A$

Substitute $C = 2A$ in (1) and (2)

$C + S + A = 329$ -- (1)

$2A + S + A = 329$

$3A + S = 329$

Make S the subject

$S = 329 - 3A$

$5C + 7S + 12A = 2388$ -- (2)

$5*2A + 7S + 12A = 2388$

$10A + 7S + 12A = 2388$

$7S + 22A = 2388$

Substitute $S = 329 - 3A$

$7(329 - 3A) + 22A = 2388$

$2303 - 21A + 22A = 2388$

$2303 +A = 2388$

Solve for A

$A = 2388 - 2303$

$A = 85$

Recall that: $C = 2A$

$C = 2 * 85$

$C = 170$

Recall that: $S = 329 - 3A$

$S = 329 - 3 * 85$

$S = 329 - 255$

$S = 74$

Hence, the result is:

$C = 170$

$S = 74$

$A = 85$

8 0

3 years ago