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3 years ago

Find the area of a circle centered at the origin that passes through the point -3,5.

Mathematics

1 answer:

natulia [17]3 years ago

4 0

Idk....................................................

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A train travels 220 miles in 4 hours. What is the train's speed in feet per minute?

Katena32 [7]

220 miles in 4 h = 55 mph multiply this by 5280 to get feet per hour then divide this by 60 to get ft/min

7 0

4 years ago

Read 2 more answers

7 and 12 Find the measure of angle x. Round your answer to the nearest hundredth. (please type the numerical answer only) (30 Po

goldfiish [28.3K]

Answer:

Angle Y = 35.69 degrees

Step-by-step explanation:

We can use some simple trigonometry to help us out. Here we know that side 7 is the opposite side relative to angle y, and 12 is the hypotenuse.

We think what trig ratio involves comparing opposite and hypotenuse. Sine is opposite over hypotenuse and we can set up a equation to solve.

Sine (Angle Y) = Opposite Side / Hypotenuse

Sine (Angle Y) = 7/12

(Angle Y) = Sine inverse (7/12)

Angle Y = 35.69

8 0

2 years ago

Question 2: Ethan has a collection of 50 DVDs. If 32 of the DVDs are comedies, what percent of the DVDs are not comedies?

gladu [14]

Answer: 36% are not comedies

Step-by-step explanation:

32/50 = 64%

100 - 64 = 36

3 0

2 years ago

Can someone help me with this question

trasher [3.6K]

Answer:

30 ft

Step-by-step explanation:

Multiply the scale factor by the wall given.

45 X 8 in = 360 in

Convert inches into feet. (12 inches = 1 foot)

360/12 = 30 feet

5 0

4 years ago

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Element X decays radioactively with a half life of 12 minutes. If there are 200 grams of Element X, how long, to the nearest ten

Semenov [28]

Answer:

It would take 24 minutes for the element to decay to 50 grams

Step-by-step explanation:

The equation for the amount of the element present, after t minutes, is:

$Q(t) = Q(0)e^{-rt}$

In which Q(X) decays radioactively with a half life of 12 minutes.(0) is the initial amount and r is the rate it decreases.

Half life of 12 minutes

This means that $Q(12) = 0.5Q(0)$

$Q(t) = Q(0)e^{-rt}$

$0.5Q(0) = Q(0)e^{-12r}$

$e^{-12r} = 0.5$

$\ln{e^{-12r}} = \ln{0.5}$

$-12r = \ln{0.5}$

$12r = -\ln{0.5}$

$r = -\frac{\ln{0.5}}{12}$

$r = 0.05776$

If there are 200 grams of Element X, how long, to the nearest tenth of a minute, would it take the element to decay to 50 grams?

This is t when Q(t) = 50. Q(0) = 200.

$Q(t) = Q(0)e^{-rt}$

$50 = 200e^{-0.05776t}$

$e^{-0.05776t} = 0.25$

$\ln{e^{-0.05776t}} = \ln{0.25}$

$-0.05776t = \ln{0.25}$

$0.05776t = -\ln{0.25}$

$t = -\frac{\ln{0.25}}{0.05776}$

$t = 24$

It would take 24 minutes for the element to decay to 50 grams

6 0

4 years ago