Answer:
E) Either anaphase I or II
Explanation:
Failure of segregation of homologous chromosomes during anaphase I or failure of segregation of sister chromatids during anaphase II leads to the presence of the abnormal number of chromosomes in resultant gametes. In the given example, the egg mother cell with 48 chromosomes (24 pairs) would enter meiosis I but the failure of one pair of homologous chromosomes to segregate from each other followed by normal meiosis II would result in the formation of two gametes with one extra chromosome and two gametes with one less chromosome.
On the other hand, if the nondisjunction occurs at anaphase II of meiosis II, two normal gametes, one gamete with one extra chromosome and one gamete with one less chromosome will be formed. Therefore, nondisjunction at anaphase I or anaphase II would have resulted in the production of eggs with one extra chromosome.
Let's think of it like this. We have an energy crisis, but how can we solve it? There are three steps. First, we need to recognize that we HAVE a problem that needs to be fixed. Then, we need to determine what's causing the problem. Finally, we need to change how we act in order to solve the problem. Now, let's look at the options.
Is A correct, leaving our behavior unchanged? NO: if we know the cause of the problem, we still need to solve it! What about B: the problems are ignored? NO: you can't solve a problem unless you know it's a problem. C? NO: to solve a problem, you need to find out what's causing it. Finally, let's look at D: behavior is changed after cause is identified. This is correct: not only do we know why it's happening, but we're fixing it!
Answer: D
Out of the choices given, the two Middle Eastern people that can be referred to as a Semite is the Jews and the Persians. This will make the correct answer D.
