The population seems like a young age group.
Answer: who made this question I think you need to round 250 to the nearest whole number I’m not sure.
Step-by-step explanation:
The probability that all of the next ten customers who want this racket can get the version they want from current stock is 0.821
<h3>How to solve?</h3>
Given: currently has seven rackets of each version.
Then the probability that the next ten customers get the racket they want is P(3≤X≤7)
<h3>Why P(3≤X≤7)?</h3>
Note that If less than 3 customers want the oversize, then more than 7 want the midsize and someone's going to miss out.
X ~ Binomial (n = 10, p = 0.6)
P(3≤X≤7) = P(X≤7) - P(X≤2)
From Binomial Table:
= 0.8333 - 0.012
= 0.821
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First, let us restate the given conditions
c is 5 more than variable a ( c = a + 5)
c is also three less than variable a (c = a - 3)
Now, lets look at the answer choices and or given
c = a − 5
c = a + 3
Here, c is 5 less than "a"...so automatically disqualified
a = c + 5
a = 3c − 3
Here, we have to get "C" by itself in both top and bottom equation.
So,
Simplified version :
c = a - 5
Here, c is 5 less than "a"...so automatically disqualified
a = c − 5
a = 3c + 3
Here also, we have to get "C" by itself in both top and bottom equation.
So,
simplified version:
c = a + 5
Here, c is 5 more than "a"...so we continue
c = (a - 3) / 3
Here, c is 3 less than "a" <u>divided by 3</u><u /> . So, this is not correct
c = a + 5
c = a − 3
Here, c is 5 more than "A"
Also, c is 3 less than "a"
Which satisfies the given.
So, our answer is going to be the last one:
c = a + 5
c = a - 3
Answer:
Andre's Method is the only one that works
Step-by-step explanation:
Noah's method won't work because he doesn't follow the order of operations. You can pull the the 9 out first you have to distribute the 2 first.
Elena's method doesn't work because to eliminate the 18 you must use the reverse operation it must be added not subtracted.
Andre's Method is the only one that works