This happens whenever
or
. More generally,
whenever you start with one of these angles and add any multiple of
, so the general solution would be
, where
is any integer. (Notice that when
, you end up with
.)
Answer:
40 problems in 100 minutes
Step-by-step explanation:
This is a ratio problem.
You first divide 30 minutes by three to get how many problems she can do in 10 minutes. What you do to one side you do to the other side. So then, you should have 4 problems in 10 minute. Then, you multiply 10 by 10 and 4 by 10 to get 40 problems in 100 minutes.
Answer:
4.04 metros
Step-by-step explanation:
Resolvemos la pregunta anterior usando la función trigonométrica de
tan θ = Opuesto / Adyacente
θ = 60 °
Frente = 7 metros
Adyacente =? = x
Por eso
bronceado 60 = 7 / x
Multiplicar cruzada
= tan 60 × x = 7
x = 7 / tan 60
x = 4.0414518843 metros
Aproximadamente = 4.04 metros
Answer:
a + b + c + d = 230
Step-by-step explanation:
So first, I am going to write down everything that I can find out from the picture.
a + b = 115
c + d + (180 - a) + (180 - b) = 360
Now, I can use a + b = 115 to simplify c + d + (180 - a) + (180 - b) = 360.
c + d + (360 - (a + b)) = 360
c + d + (360 - 115) = 360
c + d +245 = 360
c + d = 115
Now I know that:
a + b = 115
c + d = 115
Now I can find a + b + c + d
a + b + c + d = (a + b) + (c + d) = 115 + 115 = 230
a + b + c + d = 230
The halves of the rhombus separated by line BD are equilateral triangles.
∠BAD = 60°
so
∠ADM is 0.80*60° = 48°.
∠BMD is an exterior angle to ΔAMD, so is equal to the sum
∠BMD = ∠BAD + ∠ADM
= 60° +48° = 108°
∠BMD = 108°
