When solving a literal equation, what is the trick for isolating a variable that appears more than once?
2 answers:
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If those two are your only choices then the answer is none of the above.
<em>Attached is a cumulative frequency table for your data.</em>
If you take a look at the two tables given, the frequencies were not tallied properly. If the frequency column is wrong, then the cumulative frequency will be wrong.
The answer is then none of the above or find one that matches the table attached.
<em>Attached is a cumulative frequency table for your data.</em>
If you take a look at the two tables given, the frequencies were not tallied properly. If the frequency column is wrong, then the cumulative frequency will be wrong.
The answer is then none of the above or find one that matches the table attached.
Answer:
See attached
Step-by-step explanation:
Given function:
- y = -2x² + 5x + 8
Table and graph are attached
Zeros are included in the graph
<u>Zero's are obtained:</u>
x = 0 ⇒ y = 8
y = 0 ⇒ Solving quadratic equation
- -2x² + 5x + 8 = 0
- x = (-5 ± √(25 + 2*4*8))/-4
- x = 3.608
- x = -1.108
So zeros are (0, 8), (3.608, 0) and (-1.108, 0)
