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Rudiy27
3 years ago
14

When solving a literal equation, what is the trick for isolating a variable that appears more than once?

Mathematics
2 answers:
schepotkina [342]3 years ago
5 0

What the first guy said

Paha777 [63]3 years ago
4 0

Literal equations, simply put, are equations containing two or more variables. Your goal is to solve for just one variable with respect to others. If you know how to solve regular equations, then I guarantee you that solving literal equations will be a breeze.

The "heart" of literal equation is to isolate or keep by itself a certain variable on one side of the equation (either left or right) and the rest on the opposite side. 

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Find the equivalent expression using the same bases (97*59)^9
irina [24]

Answer:

Exact form : 5723^9

Decimal form : 6.58587848 • 10^33

Step-by-step explanation: Evaluate.

Hope this helps you out! ☺

4 0
3 years ago
Do you know how to solve this with work to back it up?
ehidna [41]
Depends are you finding x or other variables
5 0
3 years ago
A spinner has 10 equally sized sections, 4 of which are gray and 6 of which are blue. The spinner is spun twice. What is the pro
wariber [46]

Answer:

1/2 beacuse its each have a possibility tobe land on and the most best answer wpuld be 1/2 i tryed ok

4 0
3 years ago
use the intermediate value theorem to determine whether the following equation has a solution or not x^3-3x-1
xxTIMURxx [149]

Answer:

Yes, this equation has a solution. According to Intermediate Value Theorem at least one solution for [0,2]

Step-by-step explanation:

Hi there!

1) Remember a definition.

Intermediate Value Theorem:

If f is continuous on a given closed interval [a,b], and f(a)≠f(b) and f(a)<k<f(b) then there has to be at least one number 'c' between 'a' and 'b', such that f(c)=k

----

(Check the first graph as an example)

2) The Intermediate Value Theorem can be applied to determine whether there is a solution on a given interval.

Let's choose the interval [0,2]

f(x)=x^{3}-3x-1\\f(0)=(0)^{3}-3(0)-1\\f(0)=-1\\f(0)

Proceed to the other point: 2

f(x)=x^{3}-3x-1\\f(2)=(2)^{3}-3(2)-1\\f(2)=1\\f(2)>0\\

3) Check the 2nd Graph for a the Visual answer, of it.  And the 3rd graph for all solutions of this equation.

3 0
3 years ago
Find the surface area of a cylinder with a base radius of 2 cm and a height of 8 cm
gtnhenbr [62]

Answer:

82.6cm2

Step-by-step explanation:

\pi {r}^{2}  + \pi {r}^{2}  + 2  \pi \: r h

\pi =  \frac{22}{7}

radius =2cm

height=8cm

( \frac{22}{7}  \times 2 \times 2 )+ ( \frac{22}{7}  \times 2 \times 2) + (2 \times  \frac{22}{7}  \times 2 \times 8)

Multiplying the numerators and The whole numbers, we have

\frac{88}{7}  +  \frac{88}{7}  +  \frac{402}{7}

Since the denominators of the fractions are the same, we add the numerators.

\frac{88 + 88 + 402}{7}  =  \frac{578}{7}  \\ which \: becomes \\

82.57{cm}^{2}  = 82.6 {cm}^{2}

6 0
3 years ago
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