Answer:
The answer is C. Pepsin becomes inactive as soon as it reaches small intestine.
Explanation:
Enzymes are pH specific. They once work at those specific values and if those are changed they either degrade or become inactive. The pH of stomach is acidic and that of the small intestine is basic. Therefore the enzymes will become inactive when it enters small intestine.
The correct answer is E)52
When there is Hardy-Weinberg equilibrium like in this case of a single locus with two alleles denoted A and a with frequencies f(A) = p and f(a) = q, the expected genotype frequencies under random mating are f(AA) = p² for the AA homozygotes, f(aa) = q² for the aa homozygotes, and f(Aa) = 2pq for the heterozygotes. Let's put that A is dominant and a is recessive allele. In Hardy-Weinberg equilibrium we have:
p²+2*p*q+q²= 1 p+q=1 p=1-q
f(a) =0.4=q q²=0.4²=0.16=16%
p= 1-0.4=0.6 p²=0.6²=0.36=36%
Percentage of a homozygous genotype in the population is 16%+36%=52%
I think 75% or 90% (I looked it up lol)
The 3 can only be produced in the Mediterranean biome. This biome is known to have dry and wet weather. However, the summer seasons in this biome is very dry and usually lasts longer. Hence, the vegetation is found to be drought resistant. The 3 plants mentioned are known to be naturally drought resistant, hence it is in this biome that it thrives and survives best.
C raccoons because they eat a wide variety because they can adapt more easily than other populations
