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nadya68 [22]
3 years ago
8

What is the solution to the system of equations shown below 2x-y+z=4 4x-2y+2z=8 -x+3y-z+=5

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
8 0

Answer:

Step-by-step explanation:

2x - y + z = 4

4x - 2y + 2z = 8

-x + 3y - z = 5

2x - y  + z = 4

-x + 3y - z = 5

x + 2y = 9

4x - 2y + 2z = 8

-2x + 6y - 2z = 10

2x + 4y = 18

x + 2y = 9

2x + 4y = 18

-2x - 4y = -18

2x + 4y = 18

0 =0

infinitely many solutions

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Alisiya [41]
Let y=C_1x+C_2x^3=C_1y_1+C_2y_2. Then y_1 and y_2 are two fundamental, linearly independent solution that satisfy

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Note that {y_1}'=1, so that x{y_1}'-y_1=0. Adding y'' doesn't change this, since {y_1}''=0.

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Find the term that must be added to the equation x2 6x=1 to make it into a perfect square.
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The value added to the equation $x^2-6x=1 exists $x^2-6x+9=10.

<h3>What is a perfect square?</h3>

A perfect square exists as a number that can be described as the product of an integer by itself or as the second exponent of an integer.

The perfect square trinomial exists

(a ± b)^2 = a ^2 ± 2ab + b ^2

$x^2-6x=1

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then $2ab = 2 * 3*x = 2 * x *3

The value of a = x and b = 3

$b^2=3^2=9

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$x^2-6x+9=10

The value added to the equation $x^2-6x=1 exists $x^2-6x+9=10.

To learn more about perfect square refer to: brainly.com/question/6946048

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