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3 years ago

What is the solution to the system of equations shown below 2x-y+z=4 4x-2y+2z=8 -x+3y-z+=5

Mathematics

1 answer:

jok3333 [9.3K]3 years ago

8 0

Answer:

Step-by-step explanation:

2x - y + z = 4

4x - 2y + 2z = 8

-x + 3y - z = 5

2x - y + z = 4

-x + 3y - z = 5

x + 2y = 9

4x - 2y + 2z = 8

-2x + 6y - 2z = 10

2x + 4y = 18

x + 2y = 9

2x + 4y = 18

-2x - 4y = -18

2x + 4y = 18

0 =0

infinitely many solutions

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Evaluate the expression if a=2,b=-3,C=-1, and D=4<br><br><br> -2(b^2-5c)

Alenkasestr [34]

$\qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star$

Equivalent value = -28

$\textsf{ \underline{\underline{Steps to solve the problem} }:}$

$\qquad❖ \: \sf \: - 2( {b}^{2} - 5c)$

( put the values )

$\qquad❖ \: \sf \: - 2 \{( - 3) {}^{2} - 5( - 1) \}$

$\qquad❖ \: \sf \: - 2(9 - (- 5))$

$\qquad❖ \: \sf \: - 2(9 + 5)$

$\qquad❖ \: \sf \: - 2 \times 14$

$\qquad❖ \: \sf \: - 28$

$\qquad \large \sf {Conclusion} :$

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1 year ago

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stiv31 [10]

ANSWER

a=-2, b=3

EXPLANATION

The given equation is

$(a {x}^{2})( - 6 {x}^{b} ) = 12 {x}^{5}$

Recall that:

${a}^{m} \times {a}^{n} = {a}^{m + n}$

We simplify the left hand side to get:

$- 6a {x}^{2 + b} = 12 {x}^{5}$

For this equation to be true, we must have:

-6a=12 and 2+b=5

This implies that,

a=-2 and b=3

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3 years ago