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2 years ago

Whats the key way to resolve reading math problems

2 answers:

7 0

I would say to read the question carefully and draw a graph or underline the key details in the question. If you don't get it, than cross out the answer choices that you KNOW for certain is wrong. This way, you have a better chance of getting the question right. Also, create a algebra expression if that works for you!
I hope this helped!

Lady bird [3.3K]2 years ago

6 0

I would say read it well and then write down an equation or expression to represent the data so its easier for you to understand and/or solve.

You might be interested in

Find the polynomial of minimum degree, with real coefficients, zeros at x=4+4i and x=2, and y-intercept at 64

Mice21 [21]

Answer:

$\displaystyle -x^3+10x^2-48x+64$

Step-by-step explanation:

We want to find the minimum-degree polynomial with real coefficients and zeros at:

$x= 4+4i\text{ and } x = 2$

As well as a y-intercept of 64.

By the Complex Root Theorem, if a + bi is a root, then a - bi is also a root.

So, a third root will be 4 - 4i.

The factored form of a polynomial is given by:

$P(x)=a(x-p)(x-q)...$

Where a is the leading coefficient and p and q are the zeros. More factors can be added if necessary.

Substitute:

$P(x)=a(x-(2))(x-(4+4i))(x-(4-4i))$

Since we want the minimum degree, we won't need to add any exponents.

Expand the second and third factors:

$\displaystyle \begin{aligned} (x-(4+4i))(x-(4-4i))&=(x-4-4i)(x-4+4i) \\ &= x(x-4-4i)-4(x-4-4i)+4i(x-4-4i)\\ &=x^2-4x-4ix-4x+16+16i+4ix-16i-16i^2\\ &= x^2-8x+32\end{aligned}$

Hence:

$P(x)=a(x-2)(x^2-8x+32)$

Lastly, we need to determine a. Since the y-intercept is y = 64, this means that when x = 0, y = 64. Thus:

$64=a(0-2)(0^2-8(0)+32)$

Solve for a:

$-64a=64\Rightarrow a=-1$

Our factored polynomial is:

$P(x)=-(x-2)(x^2-8x+32)$

Finally, expand:

$\displaystyle \begin{aligned} P(x) &=-(x^2(x-2)-8x(x-2)+32(x-2)) \\&=-(x^3-2x^2-8x^2+16x+32x-64)\\&=-(x^3-10x^2+48x-64)\\&= -x^3+10x^2-48x+64\end{aligned}$

8 0

2 years ago

SURDS

aev [14]

1) √3 √7 = √21
2) √5 √245 = √5 √5 * 49 = √5 * 7√5 = 7 √5 * 5 = 7 √25 = 7 * 5 = 35
3) √77 ÷ √11 = as is. can't be simplified.
4) (√59)² = 59 ; the square root was cancelled by squared.
5) 3√6 x 8√7 = 3 * 8 √6 * 7 = 24 √42
6) 5√3 x 6 √3 = 5 * 6 √3 * 3 = 30 √9 = 30 * 3 = 90
7) 40√30 ÷ 5√3 = (40 / 5) * (√30 /√3) = 8 * ((√3 *10) / √3) = 8 √10
8) (6√5)² = 6² * √5² = 36 * 5 = 180

4 0

2 years ago

In a right triangle, the length of one leg is 6 units. The length of the other leg is 8 units. What is the length of the hypoten

lozanna [386]

$hypotenuse = \sqrt{6^2+8^2}= \sqrt{36+64}= \sqrt{100}=10 \ units$