is in quadrant I, so
.
is in quadrant II, so
.
Recall that for any angle
,

Then with the conditions determined above, we get

and

Now recall the compound angle formulas:




as well as the definition of tangent:

Then
1. 
2. 
3. 
4. 
5. 
6. 
7. A bit more work required here. Recall the half-angle identities:



Because
is in quadrant II, we know that
is in quadrant I. Specifically, we know
, so
. In this quadrant, we have
, so

8. 
Answer: NO GRAPH DUMMY
Step-by-step explanation:
This is what I got hope u get it right gl
Answer:
y=5/3x-13
Step-by-step explanation:
We must use the point-slope form(parallel lines have the same slope, remember that!)
y-y1=m(x-x1)
y-2=5/3(x-9)
y-2=5/3x-15
y=5/3x-13