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PilotLPTM [1.2K]

3 years ago

15

What is the answer to this problem ? -5k(5k+4)=25-10k

1 answer:

drek231 [11]3 years ago

5 0

Answer:

no real solutions

Step-by-step explanation:

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Please help Fast A parking lot contains motorcycles (2 Wheels) and cars (4 Wheels). There are 35 vehicles and 114 wheels. How ma

swat32

Answer: There will be 20 motorcycles and 26 cars

let me know if you want me to explain:)

Step-by-step explanation:

If you want to check multiply 26 by the amount of wheels on each car (4) to get 104 total car wheels, then multiply the 20 motorcycles by the wheels of each motorcycle (2) to get 40. Lastly add the 104 and 40 together to get 144 the total amount of wheels in the parking lot.

Hope this helps :)

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3 years ago

A number cube is rolled 24 times and lands on 2 four times and on 6 three times.

kozerog [31]

Answer:

1/6 times the number cube wil land on 2

Step-by-step explanation:

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3 years ago

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iogann1982 [59]

Answer:

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Step-by-step explanation:

Use a calculator to guess and check

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3 years ago

6 over 7 subtracted by 1 over 7

Rus_ich [418]

Answer:

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Step-by-step explanation:

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4 years ago

Read 2 more answers

A colony of bacteria is growing at a rate of 0.2 times its mass. Here time is measured in hours and mass in grams. The mass of t

11Alexandr11 [23.1K]

Answer:

<u>Question 1:</u> $dm/dt=0.2m$ <u />

<u />

<u>Question 2:</u> $m=Ae^{(0.2t)}$ <u />

<u />

<u>Question 3:</u> $m=10e^{(0.2t)}$ <u />

<u />

<u>Question 4:</u> $m=10g$ <u />

Explanation:

<u>Question 1: Write down the differential equation the mass of the bacteria, m, satisfies: m′= .2m</u>

<u></u>

a) By definition: $m'=dm/dt$

b) Given: $rate=0.2m$

c) By substitution: $dm/dt=0.2m$

<u>Question 2: Find the general solution of this equation. Use A as a constant of integration.</u>

a) <u>Separate variables</u>

$dm/m=0.2dt$

b)<u> Integrate</u>

$\int dm/m=\int 0.2dt$

$ln(m)=0.2t+C$

c) <u>Antilogarithm</u>

$m=e^{0.2t+C}$

$m=e^{0.2t}\cdot e^C$

$e^C=A\\\\m=Ae^{(0.2t)}$

<u>Question 3. Which particular solution matches the additional information?</u>

<u></u>

Use the measured rate of 4 grams per hour after 3 hours

$t=3hours,dm/dt=4g/h$

First, find the mass at t = 3 hours

$dm/dt=0.2m\\\\4=0.2m\\\\m=4/0.2\\\\m=20g$

Now substitute in the general solution of the differential equation, to find A:

$m=Ae^{(0.2t)}\\\\20=Ae^{(0.2\times 3)}\\\\A=20/e^{(0.6)}\\\\A=10.976$

Round A to 1 significant figure:

A = 10.

<u>Particular solution:</u>

$m=10e^{(0.2t)}$

<u>Question 4. What was the mass of the bacteria at time =0?</u>

Substitute t = 0 in the equation of the particular solution:

$m=10e^{0}\\\\m=10g$

3 0

3 years ago