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PilotLPTM [1.2K]
3 years ago
15

What is the answer to this problem ? -5k(5k+4)=25-10k

Mathematics
1 answer:
drek231 [11]3 years ago
5 0

Answer:

no real solutions

Step-by-step explanation:

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Answer: There will be 20 motorcycles and 26 cars

let me know if you want me to explain:)

Step-by-step explanation:

If you want to check multiply 26 by the amount of wheels on each car (4) to get 104  total car wheels, then multiply the 20 motorcycles by the wheels of each motorcycle (2) to get 40. Lastly add the 104 and 40 together to get 144 the total amount of wheels in the parking lot.

Hope this helps :)

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3 years ago
A number cube is rolled 24 times and lands on 2 four times and on 6 three times.
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1/6 times the number cube wil land on 2

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
6 over 7 subtracted by 1 over 7
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Step-by-step explanation:

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5 0
4 years ago
Read 2 more answers
A colony of bacteria is growing at a rate of 0.2 times its mass. Here time is measured in hours and mass in grams. The mass of t
11Alexandr11 [23.1K]

Answer:

  • <u>Question 1:</u>      dm/dt=0.2m<u />

<u />

  • <u>Question 2:</u>     m=Ae^{(0.2t)}<u />

<u />

  • <u>Question 3:</u>      m=10e^{(0.2t)}<u />

<u />

  • <u>Question 4:</u>      m=10g<u />

Explanation:

<u>Question 1: Write down the differential equation the mass of the bacteria, m, satisfies: m′= .2m</u>

<u></u>

a) By definition:  m'=dm/dt

b)  Given:  rate=0.2m

c) By substitution:  dm/dt=0.2m

<u>Question 2: Find the general solution of this equation. Use A as a constant of integration.</u>

a) <u>Separate variables</u>

     dm/m=0.2dt

b)<u> Integrate</u>

           \int dm/m=\int 0.2dt

            ln(m)=0.2t+C

c) <u>Antilogarithm</u>

       m=e^{0.2t+C}

       m=e^{0.2t}\cdot e^C

         e^C=A\\\\m=Ae^{(0.2t)}

<u>Question 3. Which particular solution matches the additional information?</u>

<u></u>

Use the measured rate of 4 grams per hour after 3 hours

            t=3hours,dm/dt=4g/h

First, find the mass at t = 3 hours

            dm/dt=0.2m\\\\4=0.2m\\\\m=4/0.2\\\\m=20g

Now substitute in the general solution of the differential equation, to find A:

          m=Ae^{(0.2t)}\\\\20=Ae^{(0.2\times 3)}\\\\A=20/e^{(0.6)}\\\\A=10.976

Round A to 1 significant figure:

  • A = 10.

<u>Particular solution:</u>

           

             m=10e^{(0.2t)}

<u>Question 4. What was the mass of the bacteria at time =0?</u>

Substitute t = 0 in the equation of the particular solution:

         m=10e^{0}\\\\m=10g

3 0
3 years ago
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