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kaheart [24]
2 years ago
8

Can someone give me the answer with work to this problem?

Mathematics
1 answer:
77julia77 [94]2 years ago
6 0

Answer:

x=10

Step-by-step explanation:

4x-18=3x-8

4x-3x=-8+18

x=10

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A circle has a center at (5, 5) and a radius of 2. If the format of the equation for the circle is (x − h)2 + (y − k)2 = r2, the
earnstyle [38]

Answer:

D:  r^2 = 4

Step-by-step explanation:

Square the radius:  r^2 = 2^2 = 4 (answer)

5 0
3 years ago
The equation of the line pass through the points (-4,2) and (-5,2) is
ivanzaharov [21]

Answer:

  y = 2

Step-by-step explanation:

Both points are on the horizontal line ...

  y = 2

__

<em>Additional comment</em>

A horizontal line has equation y = constant. A vertical line has equation x = constant.

7 0
2 years ago
Read 2 more answers
Russell has a collection of 1,200 pennies. Of these pennies, 25% are dated before 1980, 35% are dated from 1980 to 2000, and the
STatiana [176]
480 pennies.

25% are dated before 1980, therefore:
1200(total):100 = 12 (1%)
12(1%)x25 = 300 (25%)

35% are dated from 1980 to 2000, therefore:
12(1%)x35 = 420 (35%)

25% are dated before 1980, 35% are dated from 1980 to 2000 and the rest are dated after 2000.
25% + 35% = 60%.
300(25%) + 420(35%) = 720.
60% = 720.
100%-60% = 40%.
40% is the amount of pennies that are dated after 2000.

The total (100%) of the pennies is 1200.
We also know that 60% of the total (1200) is 720.

1200(100%) - 720(60%) = 480(40%).

Therefore, the amount of pennies dated after 2000 in Russell’s Collection is 480.
7 0
3 years ago
Find the polynomial of minimum degree, with real coefficients, zeros at
drek231 [11]

Answer:

\huge\boxed{p(x)=4x^3-20x^2+4x+300}

Step-by-step explanation:

\text{If}\ x=4\pm3i\ \text{and}\ x=-3\ \text{are the zeros of a polynomial, then it has  a form:}\\\\p(x)=\bigg(x-(4-3i)\bigg)\bigg(x-(4+3i)\bigg)\bigg(x-(-3)\bigg)\bigg(r(x)\bigg)\\\\p(x)=(x-4+3i)(x-4-3i)(x+3)\bigg(r(x)\bigg)\\\\p(x)=\underbrace{\bigg((x-4)+3i\bigg)\bigg((x-4)-3i\bigg)}_{\text{use}\ (a+b)(a-b)=a^2-b^2}(x+3)\bigg(r(x)\bigg)\\\\p(x)=\bigg((x-4)^2-(3i)^2\bigg)(x+3)\bigg(r(x)\bigg)\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2

p(x)=(x^2-2(x)(4)+4^2-3^2i^2)(x+3)\bigg(r(x)\bigg)\qquad\text{use}\ i^2=-1\\\\p(x)=(x^2-8x+16-9(-1))(x+3)\bigg(r(x)\bigg)\\\\p(x)=(x^2-8x+16+9)(x+3)\bigg(r(x)\bigg)\\\\p(x)=(x^2-8x+25)(x+3)\bigg(r(x)\bigg)\qquad\text{use FOIL}:\ (a+b)(c+d)=ac+ad+bc+bd\\\\p(x)=\bigg((x^2)(x)+(x^2)(3)+(-8x)(x)+(-8x)(3)+(25)(x)+(25)(3)\bigg)\bigg(r(x)\bigg)\\\\p(x)=(x^3+3x^2-8x^2-24x+25x+75)\bigg(r(x)\bigg)\qquad\text{combine like terms}\\\\p(x)=(x^3-5x^2+x+75)\bigg(r(x)\bigg)

\text{The y-intercept is at 300}.\\\\\text{For}\ w(x)=a_nx^n+a_{n-1}x^{n-1}+a_{n-2}x^{n-2}+...+a_1x+a_0\\\\\text{y-intercept is}\ a_0\\\\\text{Therefore for}\ p(x)=(x^3-5x^2+x+75)\bigg(r(x)\bigg)\\\\\text{y-intercet is}\ 75\bigg(r(x)\bigg)\\\\75\bigg(r(x)\bigg)=300\qquad\text{divide both sides by 75}\\\\r(x)=4\\\\\text{Finally:}\\\\p(x)=(x^3-5x^2+x+75)(4)\qquad\text{use the distributive property}\\\\p(x)=(x^3)(4)+(-5x^2)(4)+(x)(4)+(75)(4)\\\\p(x)=4x^3-20x^2+4x+300

7 0
3 years ago
I’m stuck please help ? Due tomorrow
Shkiper50 [21]
Here are two ways of doing it.

************************************************************

1) The current price is 100% of the price. The price went down by 6%, so since 100% - 6% = 94%, the new price is 94% of the original price.

94% * 175 = 0.94 * 175 = 164.50

The new price is 164.50

*******************************************************

2) The discount is 6% of 175, so first, we find the discount.

6% of 175 = 0.06 * 175 = 10.5

Now we subtract the amount of the discount from the original price.

175 - 10.50 = 164.50

The new price is 164.50

**********************************************************

As you can see, both methods give you the same answer, 164.50
6 0
3 years ago
Read 2 more answers
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