Can someone give me the answer with work to this problem?
1 answer:
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Answer:
∠BKM= ∠ABK
Therefore AB ║KM (∵ ∠BKM= ∠ABK and lies between AB and KM and BK is the transversal line)
m∠MBK ≅ m∠BKM (Angles opposite to equal side of ΔBMK are equal)
Step-by-step explanation:
Given: BK is an angle bisector of Δ ABC. and line KM intersect BC such that, BM = MK
TO prove: KM ║AB
Now, As given in figure 1,
In Δ ABC, ∠ABK = ∠KBC (∵ BK is angle bisector)
Now in Δ BMK, ∠MBK = ∠BKM (∵ BM = MK and angles opposite to equal sides of a triangle are equal.)
Now ∵ ∠MBK = ∠BKM
and ∠ABK = ∠KBM
∴ ∠BKM= ∠ABK
Therefore AB ║KM (∵ ∠BKM= ∠ABK and BK is the transversal line)
Hence proved.
Answer with Step-by-step explanation:
We are given that n and m are two integers
We have to prove that if n-m is even , then is also even.
We know that sum of two odd numbers is even.Sum of an odd number and even number is odd.
Product of an odd number and even number is even.
Case 1.Suppose m and n are both even n=4 , m=2
Case 2.Suppose m odd and n odd
n=9,m=5
Hence, proved.