Answer:
Step-by-step explanation:
I am sorry but please give detailed question
Answer:
1. z = 128
2. x = 4.2
3. c = 10
4. w = 100
5. a = 95.2
Step-by-step explanation:
1. Solve for z:
z/16 = 8
Multiply both sides of z/16 = 8 by 16:
(16 z)/16 = 16×8
(16 z)/16 = 16/16×z = z:
z = 16×8
16×8 = 128:
Answer: z = 128
_____________________________________________________
2. Solve for x:
3.5 x = 14.7
Divide both sides of 3.5 x = 14.7 by 3.5:
(3.5 x)/3.5 = 14.7/3.5
3.5/3.5 = 1:
x = 14.7/3.5
14.7/3.5 = 4.2:
Answer: x = 4.2
____________________________________________
3. Solve for c:
32 = 3.2 c
32 = 3.2 c is equivalent to 3.2 c = 32:
3.2 c = 32
Divide both sides of 3.2 c = 32 by 3.2:
(3.2 c)/3.2 = 32/3.2
3.2/3.2 = 1:
c = 32/3.2
32/3.2 = 10:
Answer: c = 10
__________________________________________________
4. Solve for w:
(2 w)/5 = 40
Multiply both sides of (2 w)/5 = 40 by 5/2:
(5×2 w)/(2×5) = 5/2×40
5/2×2/5 = (5×2)/(2×5):
(5×2)/(2×5) w = 5/2×40
5/2×40 = (5×40)/2:
(5×2 w)/(2×5) = (5×40)/2
(5×2 w)/(2×5) = (2×5)/(2×5)×w = w:
w = (5×40)/2
2 | 2 | 0
| 4 | 0
- | 4 |
| | 0
| - | 0
| | 0:
w = 5×20
5×20 = 100:
Answer: w = 100
___________________________________________________
5. Solve for a:
a/14 = 6.8
Multiply both sides of a/14 = 6.8 by 14:
(14 a)/14 = 14×6.8
(14 a)/14 = 14/14×a = a:
a = 14×6.8
14×6.8 = 95.2:
Answer: a = 95.2
Answer: 99% of confidence interval for the population proportion of employed individuals who work at home at-least once per week
//0.20113,0.20887[/tex]
Step-by-step explanation:
<u>step 1:-</u>
Given sample size n=200
of the 200 employed individuals surveyed 41 responded that they did work at home at least once per week
Population proportion of employed individuals who work at home at least once per week P = 
Q=1-P= 1-0.205 = 0.705
<u>step 2:-</u>
Now 
=0.0015
<u>step 3:-</u>
<u>Confidence intervals</u>
<u>using formula</u>


=0.20113,0.20887[/tex]
<u>conclusion:</u>-
99% of confidence interval for the population proportion of employed individuals who work at home at-least once per week
//0.20113,0.20887[/tex]
Answer:
you can do a trial and improvement
Step-by-step explanation: