Let's solve this problem step-by-step.
−3(1−2x)=3x+3(x−3)+6
Step 1: Simplify both sides of the equation.
−3(1−2x)=3x+3(x−3)+6
(−3)(1)+(−3)(−2x)=3x+(3)(x)+(3)(−3)+6(Distribute)
−3+6x=3x+3x+−9+6
6x−3=(3x+3x)+(−9+6)(Combine Like Terms)
6x−3=6x+−3
6x−3=6x−3
Step 2: Subtract 6x from both sides.
6x−3−6x=6x−3−6x
−3=−3
Step 3: Add 3 to both sides.
−3+3=−3+3
0=0
So, 0=0 or all real numbers.
the formula to find the diagonal would be
a^2+b^2=c^2
3^2+4^2= 9+16=25
the square root of 25 is 5
5^2=25
so your diagonal is 5 ft
So hmm notice the picture below
one is 7x5x1.75 the volume of a rectangular prism is V = length * width * height
so 7*5*1.75 gives us 61.25 ft³
the second one, is larger by some width and length we dunno, but we know that it required that 61.25 plus an extra 17.5 to fill it up, so its volume is 61.25 + 17.5 or 78.75
the height is the same... so

so.. if you factor 45, to two factors, one will be the length, the other the width
Answer:
f) a[n] = -(-2)^n +2^n
g) a[n] = (1/2)((-2)^-n +2^-n)
Step-by-step explanation:
Both of these problems are solved in the same way. The characteristic equation comes from ...
a[n] -k²·a[n-2] = 0
Using a[n] = r^n, we have ...
r^n -k²r^(n-2) = 0
r^(n-2)(r² -k²) = 0
r² -k² = 0
r = ±k
a[n] = p·(-k)^n +q·k^n . . . . . . for some constants p and q
We find p and q from the initial conditions.
__
f) k² = 4, so k = 2.
a[0] = 0 = p + q
a[1] = 4 = -2p +2q
Dividing the second equation by 2 and adding the first, we have ...
2 = 2q
q = 1
p = -1
The solution is a[n] = -(-2)^n +2^n.
__
g) k² = 1/4, so k = 1/2.
a[0] = 1 = p + q
a[1] = 0 = -p/2 +q/2
Multiplying the first equation by 1/2 and adding the second, we get ...
1/2 = q
p = 1 -q = 1/2
Using k = 2^-1, we can write the solution as follows.
The solution is a[n] = (1/2)((-2)^-n +2^-n).
Answer:
Equation pf parallel line y = 4x + C
now this line pass through (-2,4) so it satisfies the eqn
Then, 4 = -8+C
C = 12
<h2>Hence required equation:- </h2>
<h2>y = 4x+12.....</h2>
hope it helps