3 years ago

The triangle below is isosceles. If ∠C≅∠B, then what is BC, in units?

1 answer:

6 0

BC = 10 units

If B and C are the base angles than AB and AC are congruent so set them equal to each other to solve for x. You get x = 2. Plug the 2 into the 3x+4 to get 10

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Sin α = 21/29, α lies in quadrant II, and cos β = 15/17, β lies in quadrant I Find sin (α - β).

Sever21 [200]

$\sin(\alpha-\beta)=\sin\alpha\cos\beta-\cos\alpha\sin\beta$

$\sin\alpha=\dfrac{21}{29}\implies \cos^2\alpha=1-\sin^2\alpha=\dfrac{400}{841}$

Since $\alpha$ lies in quadrant II, we have $\cos\alpha$ , so

$\cos\alpha=-\sqrt{\dfrac{400}{841}}=-\dfrac{20}{29}$

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$\beta$ lies in quadrant I, so $\sin\beta>0$ and

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The diagonals of quadrilateral ABCD intersect at point E, AE=5x-10,EC=2x+5, and BE= y/3.. If ABCD is a square, find the value of

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Check the picture below.