Question

9ax+9b-6=21 based on the equation above what is the value of ax+b

Answer 1

We have $9ax+9b-6=21$.

We add 6 to both sides. $9ax+9b=27$.

Now, to solve for $ax+b$, we factor out and divide by a 9 to get

$9(ax+b)=27 \\ ax+b=3$.