The possible digits are:
5, 6, 7, 8 and
9. Let's mark the case when the locker code begins with a prime number as
A and the case when <span>the locker code is an odd number as
B. We have
5 different digits in total,
2 of which are prime (
5 and
7).
First propability:
</span>

<span>
By knowing that digits don't repeat we can say that code is an odd number in case it ends with
5, 7 or
9 (three of five digits).
Second probability:
</span>
2.64575131106 I don’t know if you need to round the answer or not
House of Representatives. :)
Answer:
y = 2x+1 (slope-intercept form)
Step-by-step explanation:
From line B, y = 2x -2 and comparing with the general equation of line, y = mx +c, we have
m1 = 2
Parallelism rule states that m1=m2
Therefore, m2 = 2
Hence, the equation passing through point A(1,3) is
y-y1 = m2(x-X1)
y - 3 = 2(x-1)
y-3 = 2x-2
y = 2x-2+3
y = 2x+1 (slope-intercept form)