Graph the function and select the y-intercept y = 2 • 3^x a. 1 b. 2 c. 3 d. 4

To run a mile, Jamal must run 4 laps around the track. His goal is to run 3 miles. Jamal has run 9 laps so far.

vodka [1.7K]

Don’t really know what your question is but 4 laps times 3 miles is 12 laps. He’s got 3 more laps to finish his goal.

Pro tip: Include the actual question

7 0

3 years ago

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Explain your answer !! Have a nice day Will give braisnlt

Viktor [21]

Answer:

(3,-4) or x=3 and y= -4

Step-by-step explanation:

I'm going to solve this by substitution

We first need to get a variable by itself in one of the two equations (it doesn't matter which variable and the equation you do the work on doesn't matter either)

I'm going to solve for y in the second equation

-4x-4y=4

add 4y and subtract 4 from both sides to get

-4x-4=4y

Divide by 4 to get

-x-1=y

We can plug this value in for y into the first equation and get

4x+5(-x-1)= -8

Solve for x

4x-5x-5= -8

-x-5= -8

-x= -3

x=3

We can plug this value into one of the first two equations and solve for y

4(3)+5y= -8

12+5y= -8

5y= -20

y= -4

Therefore the solution is (3,-4) or x=3 and y= -4

8 0

2 years ago

You are conducting a study to see if the proportion of voters who prefer Candidate A is significantly different from 0.36. With

Dafna11 [192]

Answer:

We need to conduct a hypothesis in order to test the claim that the true proportion is 0.36 so then we need to conduct a two tailed test, the system of hypothesis are.:

Null hypothesis: $p=0.36$

Alternative hypothesis: $p \neq 0.36$

Since is a bilateral test the p value would be:

$p_v =2*P(z>2.074)=0.0381$

Step-by-step explanation:

Data given and notation n

n represent the random sample taken

$\hat p$ estimated proportion of interest

$p_o=0.36$ is the value that we want to test

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion is 0.36 so then we need to conduct a two tailed test, the system of hypothesis are.:

Null hypothesis: $p=0.36$

Alternative hypothesis: $p \neq 0.36$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion is significantly different from a hypothesized value .

Calculate the statistic

For this case the statistic is given:

$z = 2.074$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z>2.074)=0.0381$

5 0

3 years ago

______ is a common clue of law enforcement that a driver impaired

Vikentia [17]

Answer:

Step-by-step explanation: Weaving is a common clue to law enforcement that a driver is impaired

4 0

3 years ago

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If a test of H subscript 0 colon space mu subscript D equals 0 space v s. space H subscript a colon space space mu subscript D g

lara [203]

Answer:

$p_v =P(t_{(n-1)}>t_{calculated}) =0.0601$

The p value on this case is given by the problem.

If we compare the p value with a significance level assumed $\alpha=0.05$ , we see that $p_v > \alpha$ and we can conclude that we FAIL to reject the null hypothesis that the difference mean between after and before is less or equal than 0.

Step-by-step explanation:

A paired t-test is used to compare two population means where you have two samples in which observations in one sample can be paired with observations in the other sample. For example if we have Before-and-after observations (This problem) we can use it.

Let put some notation

x=test value before , y = test value after

The system of hypothesis for this case are:

Null hypothesis: $\mu_y- \mu_x \leq 0$

Alternative hypothesis: $\mu_y -\mu_x >0$

The first step is calculate the difference $d_i=y_i-x_i$

The second step is calculate the mean difference

$\bar d= \frac{\sum_{i=1}^n d_i}{n}$

The third step would be calculate the standard deviation for the differences, and we got:

$s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1}$

The 4 step is calculate the statistic given by :

$t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=t_{calculated}$

The next step is calculate the degrees of freedom given by:

$df=n-1$

Now we can calculate the p value, since we have a right tailed test the p value is given by:

$p_v =P(t_{(n-1)}>t_{calculated}) =0.0601$

The p value on this case is given by the problem.

If we compare the p value with a significance level assumed $\alpha=0.05$ , we see that $p_v > \alpha$ and we can conclude that we FAIL to reject the null hypothesis that the difference mean between after and before is less or equal than 0.

4 0

3 years ago