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svet-max [94.6K]
3 years ago
8

Name the postulate or theorem you can use to prove TKS=TLR

Mathematics
1 answer:
OlgaM077 [116]3 years ago
8 0

Answer:

ASA postulate

Step-by-step explanation:

To prove two triangles are congruent, you need 3 congruent parts in one of the patterns ASA, AAS, SSS, or SAS. Place your pencil on one vertex of the triangle then trace the figure. As you come to each congruent part, write either A for angle or S for side depending on what the part is. After doing so, you will see the pattern A - S - A since a side is congruent between two angles.

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Please answer this correctly
aleksklad [387]

Answer:

63.2 = y

Step-by-step explanation:

The perimeter is the sum of all the sides

P = 7.8+ y+37.6 + y

171.8 = 7.8+ y+37.6 + y

Combine like terms

171.8 = 45.4 + 2y

Subtract 45.4 from both sides

171.8-45.4 = 45.4 + 2y -45.4

126.4 = 2y

Divide each side by 2

126.4/2 = 2y/2

63.2 = y

6 0
3 years ago
Point B is in between A and C in a segment. AB= 22 and BC=30 Find AC
dolphi86 [110]

Answer:

AC = 52

Step-by-step explanation:

Add the segment lengths together.

AB + BC = AC

22 + 30 = 52

4 0
3 years ago
WHOEVER ANSWERS 1ST AND HAS CORRECT ANSWER WILL  GET MARKED AS BRAINILIEST
Dovator [93]
It is C. Associative property of multiplication
3 0
3 years ago
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Roman55 [17]

Answer:

12.543

Step-by-step explanation:

7 0
3 years ago
In a chess club the probability that Shaun will beat Mike is 3/8 .
romanna [79]

Answer:

\frac{10}{56} = 0.1786 probability that Shaun loses both games

Step-by-step explanation:

Games are independent, so we find each separate probability, and multiply them.

In a chess club the probability that Shaun will beat Mike is 3/8.

So 1 - \frac{3}{8} = \frac{8}{8} - \frac{3}{8} = \frac{5}{8} probability that Shaun loses.

The probability that Shaun will beat Tim is 5/7 .

So 1 - \frac{5}{7} = \frac{2}{7} probability that Shaun loses.

What is the probability that Shaun loses both games?

This is:

p = \frac{5}{8} \times \frac{2}{7} = \frac{5*2}{8*7} = \frac{10}{56} = 0.1786

\frac{10}{56} = 0.1786 probability that Shaun loses both games

3 0
3 years ago
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