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riadik2000 [5.3K]

3 years ago

15

The first catch was a touchdown and went 52 yards. The second catch was 17 yards. The last catch ended up with a loss of 10 yard

s. What is the total yardage?

1 answer:

KonstantinChe [14]3 years ago

6 0

Answer:

59 yardage

Step-by-step explanation:

52 + 17 is 69

Then that 10 yard loss would be 69 - 10 which is 59

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What is the value of x?<br> What is the measure of angle QOR?<br> What is the measure of angle ROS?

Veseljchak [2.6K]

Answer:

x = 26

angle QOR = 31

angle ROS = 59

Step-by-step explanation:

$(x + 5) + (2x + 7) = 90\\ 2x + x + 5 + 7 = 90 \\ 3x + 12 = 90 \\ 3x = 90 - 12 \\ 3x = 78 \\ x = 78 \div 3 \\ x = 26$

Sub x in

$(x + 5) \\ 26 + 5 = 31$

and

$(2 \times 26 + 7) \\ = 52 + 7 \\ = 59$

4 0

2 years ago

Use induction to prove: For every integer n > 1, the number n5 - n is a multiple of 5.

nignag [31]

Answer:

we need to prove : for every integer n>1, the number $n^{5}-n$ is a multiple of 5.

1) check divisibility for n=1, $f(1)=(1)^{5}-1=0$ (divisible)

2) Assume that $f(k)$ is divisible by 5, $f(k)=(k)^{5}-k$

3) Induction,

$f(k+1)=(k+1)^{5}-(k+1)$

$=(k^{5}+5k^{4}+10k^{3}+10k^{2}+5k+1)-k-1$

$=k^{5}+5k^{4}+10k^{3}+10k^{2}+4k$

Now, $f(k+1)-f(k)$

$f(k+1)-f(k)=k^{5}+5k^{4}+10k^{3}+10k^{2}+4k-(k^{5}-k)$

$f(k+1)-f(k)=k^{5}+5k^{4}+10k^{3}+10k^{2}+4k-k^{5}+k$

$f(k+1)-f(k)=5k^{4}+10k^{3}+10k^{2}+5k$

Take out the common factor,

$f(k+1)-f(k)=5(k^{4}+2k^{3}+2k^{2}+k)$ (divisible by 5)

add both the sides by f(k)

$f(k+1)=f(k)+5(k^{4}+2k^{3}+2k^{2}+k)$

We have proved that difference between $f(k+1)$ and $f(k)$ is divisible by 5.

so, our assumption in step 2 is correct.

Since $f(k)$ is divisible by 5, then $f(k+1)$ must be divisible by 5 since we are taking the sum of 2 terms that are divisible by 5.

Therefore, for every integer n>1, the number $n^{5}-n$ is a multiple of 5.

3 0

2 years ago

For parallelogram LMNO , if m

natali 33 [55]

I'm just going to assume you're given the volume and LMNO are sides of the parallelogram

Area = LMNO

M=?

M= $\frac{area}{LNO}$

5 0

2 years ago

In a cricket match, Rajat scored thrice as many runs as Devansh.

Rina8888 [55]

Answer:

let jivesh score x runs so rajat scores 3x runs

total runs = 300-8 = 292 runs

so x+3x = 292

4x = 292

x = 292/4

x = 73

so jivesh score 72 runs and rajat scores 216 runs

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

If abcd is dilated by a factor of 3, the coordinate of a would be?

Katyanochek1 [597]

Answer: (-9, -3)

Step-by-step explanation:

A = (-3, -1)

A' = (-3, -1)*3 = (-9, -3)

4 0

1 year ago