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4 years ago

5 POINTS!! Please answer and show work! thank you so much :)))

Mathematics

1 answer:

Liula [17]4 years ago

8 0

I could probably answer this but....

I really can't read any of the question because it is sideways and I am on a computer... Sorry... Do you mind posting it again but in the right direction? Thanks :D (also on my computer, some on the stuff is cut off...)

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Calculate the surface area of an open cuboid which is 12 cm long,8cm wide,6cm high

Vsevolod [243]

Answer:

432 cm²

Step-by-step explanation:

To find the surface area of a cuboid, there is a formula.

2lw+2lh+2hw

Length is l, height is h, and width is w.

2(12)(8)+2(12)(6)+2(6)(8)

Multiply all the terms.

336+96

Add both the terms.

= 432

The surface area of the open cuboid is 432cm².

6 0

3 years ago

Read 2 more answers

Use Midpoint and Slope Formulas to complete the tables below.1. Find the midpoint of RP, given the coordinates R (5, 8) and P (3

poizon [28]

The midpoint formula for a segment is:

$x_m,y_{_m}=\frac{(x_1+x_2)}{2},\frac{(y_1+y_2)}{2}$

apply to points R and P

$\begin{gathered} x_m,y_m=\frac{(5+3)}{2},\frac{(8+6)}{2} \\ x_m,y_m=\frac{8}{2},\frac{14}{2} \\ x_m,y_m=(4,7) \end{gathered}$

using the definition of slope find the slope of the segment

$m=\frac{y_2-y_1}{x_2-x_1}$

apply to points R and P

$\begin{gathered} m=\frac{8-6}{5-3} \\ m=\frac{2}{2} \\ m=1 \end{gathered}$

to lines are parallel when the slopes are the same

$\mleft\Vert m=1\mright?$

two lines are perpendicular when the product of the slopes is equal to -1

$\begin{gathered} m\cdot\perp m=-1 \\ 1\cdot\perp m=-1 \\ \perp m=-\frac{1}{1} \\ \perp m=-1 \end{gathered}$

7 0

2 years ago

The amount of lateral expansion (mils) was determined for a sample of n = 8 pulsed-power gas metal arc welds used in LNG ship co

Alona [7]

Answer:

95% Confidence interval for the variance:

$3.6511\leq \sigma^2\leq 34.5972$

95% Confidence interval for the standard deviation:

$1.9108\leq \sigma \leq 5.8819$

Step-by-step explanation:

We have to calculate a 95% confidence interval for the standard deviation σ and the variance σ².

The sample, of size n=8, has a standard deviation of s=2.89 miles.

Then, the variance of the sample is

$s^2=2.89^2=8.3521$

The confidence interval for the variance is:

$\dfrac{ (n - 1) s^2}{ \chi_{\alpha/2}^2} \leq \sigma^2 \leq \dfrac{ (n - 1) s^2}{\chi_{1-\alpha/2}^2}$

The critical values for the Chi-square distribution for a 95% confidence (α=0.05) interval are:

$\chi_{0.025}=1.6899\\\\\chi_{0.975}=16.0128$

Then, the confidence interval can be calculated as:

$\dfrac{ (8 - 1) 8.3521}{ 16.0128} \leq \sigma^2 \leq \dfrac{ (8 - 1) 8.3521}{1.6899}\\\\\\3.6511\leq \sigma^2\leq 34.5972$

If we calculate the square root for each bound we will have the confidence interval for the standard deviation:

$\sqrt{3.6511}\leq \sigma\leq \sqrt{34.5972}\\\\\\1.9108\leq \sigma \leq 5.8819$

6 0

3 years ago

Chanelle deposits 7500 into the bank she does not withdraw or deposit money for six years she earns 6% interest during that time

wariber [46]

Answer:

10,200 Dollars

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 6%/100 = 0.06 per year.

Solving our equation:

A = 7500(1 + (0.06 × 6)) = 10200

A = $10,200.00

3 0

3 years ago

Iready question 8 which graph does not represent a function

kondaur [170]

Answer:

The one that makes a circle

Step-by-step explanation:

5 0

3 years ago

5 POINTS!! Please answer and show work! thank you so much :)))​

5 POINTS!! Please answer and show work! thank you so much :)))