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Korvikt [17]
3 years ago
12

5 POINTS!! Please answer and show work! thank you so much :)))​

Mathematics
1 answer:
Liula [17]3 years ago
8 0

I could probably answer this but....

I really can't read any of the question because it is sideways and I am on a computer... Sorry... Do you mind posting it again but in the right direction? Thanks :D  (also on my computer, some on the stuff is cut off...)

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Solve the following system of equations using the elimination method.
never [62]

Answer:D

Step-by-step explanation:

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3 years ago
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Brianna is 2 years less than 4 times the age of Zack. If Zack's age in years is y, which expression represents Brianna's age?
alukav5142 [94]
The answer is C. 4y —2
8 0
3 years ago
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The distance dd is 11 mm. What is the perimeter of the figure? Round to the nearest tenth.
Kisachek [45]

Answer:

P = 157.1 mm

Step-by-step explanation:

The perimeter of the figure = Circumference of circle + perimeter of square

We have, d = 11

⇒ Radius = 11 mm

Side of square = 22 cm

So,

P=2\pi \times 11+4\times 22\\\\P=157.11\ mm\\\\or\\\\P=157.1\ mm

So, the perimeter of the figure is equal to 157.1 mm.

3 0
3 years ago
Ellus
mel-nik [20]

Answer:

SA = 484 cm²

Step-by-step explanation:

Surface area of the composite figure = surface area of the larger rectangular prism + (surface area of the smaller rectangular prism - base area of the smaller rectangular prism)

✔️Surface are of the larger rectangular prism = 2(LW + LH + WH)

L = 7 cm

W = 7 cm

H = 12 cm

S.A = 2(7*7 + 7*12 + 7*12) = 434 cm²

✔️Surface are of the smaller rectangular prism = 2(LW + LH + WH)

L = 7 cm

W = 2 cm

H = 2 cm

S.A = 2(7*2 + 7*2 + 2*2) = 64 cm²

✔️Base area of the smaller rectangular prism = L*W

L = 7 cm

W = 2 cm

Area = 7*2 = 14 cm²

✅Surface area of the composite figure = 434 + (64 - 14)

= 434 + 50

= 484 cm²

8 0
3 years ago
PICTURE^^ PLZ HELP !!!
densk [106]

QUESTION A

The solutions to the system of equations are the point of intersection of the quadratic graph and the straight line.

The two curves intersected at two points. Hence there are two real solutions.

The solutions are (-3,-1) and (-6,5).

QUESTION B.

The straight line is a tangent to the quadratic graph.

This means that the straight line intersected the quadratic graph at only one point.

The system has only one real solution.

The solution is (4,3).

QUESTION C

The quadratic graph and the straight line intersected at two distinct points.

The system has two real solutions.

The solutions are (0,3) and (6,-3).

QUESTION D

The two graphs are hanging apart.

There is no point of intersection.

The system has no real solutions.

QUESTION E

The straight line and the quadratic curve intersected at two distinct points.

The system has two real solutions.

The solutions are (0,0) and (1,1).

QUESTION F

The two curves intersected at only one point.

There is only one real solution to the system.

The solution is (-1,5).

3 0
3 years ago
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