Answer: option 3
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Answer: true
Step-by-step explanation: reciprocal of 3/4 is 4/3
Hence, 2/3 × 4/3 = 8/9
Answer:
a) ![t_{\alpha}= 1.753](https://tex.z-dn.net/?f=%20t_%7B%5Calpha%7D%3D%201.753)
b) ![t_{\alpha}= -1.383](https://tex.z-dn.net/?f=%20t_%7B%5Calpha%7D%3D%20-1.383)
c) ![t_{\alpha/2}= \pm 2.179](https://tex.z-dn.net/?f=%20t_%7B%5Calpha%2F2%7D%3D%20%5Cpm%202.179)
Step-by-step explanation:
Part a
For this case we know that the degrees of freedom are:
![df = 15](https://tex.z-dn.net/?f=%20df%20%3D%2015)
And we want a right tailed test so then we need to find in the t distribution with degrees of freedom =15 a critical value who accumulate 0.05 of the area in the right and we got:
![t_{\alpha}= 1.753](https://tex.z-dn.net/?f=%20t_%7B%5Calpha%7D%3D%201.753)
Part b
For this case the significance is
the degrees of freedom are:
![df = n-1= 10-1=9](https://tex.z-dn.net/?f=%20df%20%3D%20n-1%3D%2010-1%3D9)
And since is a left tailed test the critical value for this case would be:
![t_{\alpha}= -1.383](https://tex.z-dn.net/?f=%20t_%7B%5Calpha%7D%3D%20-1.383)
Part c
For this case the significance is
and
the degrees of freedom are:
![df = n-1= 13-1=12](https://tex.z-dn.net/?f=%20df%20%3D%20n-1%3D%2013-1%3D12)
And since is a two tailed test the critical values for this case would be:
![t_{\alpha/2}= \pm 2.179](https://tex.z-dn.net/?f=%20t_%7B%5Calpha%2F2%7D%3D%20%5Cpm%202.179)
To find the range, <em>subtract the smallest from the biggest number.</em>
The outlier is most commonly the biggest or smallest number. Obviously it is 236 in this situation.
To find how much the outlier increases the range, you need to find out the range <u>WITH and WITHOUT</u> the outlier.
Without the outlier: 39
With the outlier: 190
Then you subtract 190 - 39 because you are trying to find out how much <u>MORE RANGE</u> the outlier makes.
The answer is 151.
THEREFORE, The outlier increases the range by 151.