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Lerok [7]
3 years ago
14

(x²+y²+2xy+1)dy=(x+y)dx​

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
7 0

( {x}^{2} +  {y}^{2}  + 2xy + 1)dy = (x + y)dx \\  \frac{dy}{dx}  =  \frac{x + y}{ {x}^{2} +  {y}^{2} + 2xy + 1 }

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What proportion of a normal distribution corresponds to z scores greater than 1.04?
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We would need to look over the z table to find the area under the standard normal distribution curve to the left of z = 1.04. Then we'll subtract it from 1 to get the proportion of a normal distribution corresponding to z scores greater than 1.04.
By looking at the z table, we can see that the area to the left of z = 1.04 is 0.8508. So the proportion of a normal distribution to the right of z = 1.04 is 1 – 0.8508 =  0.1492.

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Answer:

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4 0
2 years ago
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