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3 years ago

7

The Osborn Buliding has two-thirds as many stories as the Xerox Tower. The Osborn Buliding has 20 stories. How many stories does

the Xerox Tower have ?

2 answers:

dem82 [27]3 years ago

5 0

26? Multiply 20 x 1/3, that will be 6.6

gizmo_the_mogwai [7]3 years ago

3 0

The Xerox tower has 30 stories

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denis23 [38]

Hello!

<u><em>Answer: </em></u>

<u><em>1. =-6</em></u>

<u><em>2. =39</em></u>

<u><em>3. =-603</em></u>

_________________________________________________

Explanation: This question's it's about the order of operations. It stands for p-parenthesis, e-exponents, m-multiply, d-divide, a-add, and s-subtract. It can also go left to right. (PEMDAS)

1. -4(3-1)+2

Do parenthesis first.

$(3-1)=2$

$-4*2+2$

Then do multiply left to right.

$-4*2=-8$

Add left to right.

$-8+2$

$8-2=6$

*Answer should be have negative sign.*

Answer: → $\boxed{=-6}$

______________________________________________________

2. 3⋅[(30−8)÷2+2]

Do parenthesis first.

$(30-8)=22$

$22/2+2$

Then divide left to right.

$22/2=11$

Add left to right.

$11+2=13$

Multiply left to right.

$3*13=39$

*Answer should be have positive sign.*

Answer: → $\boxed{=39}$

_____________________________________________________

3. 14(1-23)2+13

Do parenthesis first.

$(1-23)=-22$

$14(-22)*2+13$

Then, you multiply left to right.

$14(-22)=-308$

$-308*2=-616$

Add/subtract left to right.

$-616+13$

$616-13=603$

*The answer must be have a negative sign*

Answer: → $\boxed{=-603}$

____________________________________________________________

Hope this helps!

Thank you!

Have a great day!

-Charlie

7 0

3 years ago

A physics exam consists of 9 multiple-choice questions and 6 open-ended problems in which all work must be shown. If an examinee

katrin [286]

Answer: A) 1260

Step-by-step explanation:

We know that the number of combinations of n things taking r at a time is given by :-

$^nC_r=\dfrac{n!}{(n-r)!r!}$

Given : Total multiple-choice questions = 9

Total open-ended problems=6

If an examine must answer 6 of the multiple-choice questions and 4 of the open-ended problems ,

No. of ways to answer 6 multiple-choice questions

= $^9C_6=\dfrac{9!}{6!(9-6)!}=\dfrac{9\times8\times7\times6!}{6!3!}=84$

No. of ways to answer 4 open-ended problems

= $^6C_4=\dfrac{6!}{4!(6-4)!}=\dfrac{6\times5\times4!}{4!2!}=15$

Then by using the Fundamental principal of counting the number of ways can the questions and problems be chosen = No. of ways to answer 6 multiple-choice questions x No. of ways to answer 4 open-ended problems

= $84\times15=1260$

Hence, the correct answer is option A) 1260

5 0

3 years ago

A company has a budget of $280,000 for computing equipment. Tablets cost $500 each, laptops cost $2000 each, and servers cost $5

Kazeer [188]

Answer:

The number of tablets 200

the number of laptops 40

and, the number of servers 20

Step-by-step explanation:

Let the number of tablets be 'x'

the number of laptops be 'y'

and, the number of servers be 'z'

According to the given question

Total budget = $280,000

Tablets cost = $500 each

laptops cost = $2000 each

servers cost = $5000 each

Thus,

500x + 2000y + 5000z = 280,000 ..............(1)

also,

x = 5y ................(2)

and,

y = 2z

or

z = $\frac{\textup{y}}{\textup{2}}$ ............(3)

substituting y from 2 and 3 in equation 1, we get

(500 × 5y) + (2000 × y) + (5000 × $\frac{\textup{y}}{\textup{2}}$ ) = 280,000

or

2500y + 2000y + 2500y = 280,000

or

7000y = 280,000

or

y = 40

substituting y in equation 2, we get

x = 5 × 40 = 200

substituting y in equation 3 we get

z = $\frac{\textup{40}}{\textup{2}}$

or

z = 20

hence,

the number of tablets 200

the number of laptops 40

and, the number of servers 20

7 0

3 years ago

Their sum is 6 and their difference is 36<br> Help plz

Ivan

Answer:

Step-by-step explanation:

if you can use negative numbers then you could use 21 and -15

so

adding them together is 21 + (-15) = 6

and then subtracting 21 - (-15) =

21 + 15 = 36

do you think that would work ? :/

3 0

3 years ago

Read 2 more answers

Kevin uses 36 ounces of dried apples and 18 ounces of

aliina [53]

Answer:

6 containers

6 ounces of fruit snack will be left over

Step-by-step explanation:

1 pound = 16 ounces

⇒ ¹/₂ pound = 8 ounces

Total weight = weight of dried apples + weight of dried cranberries

= 36 + 18

= 54 ounces

Containers needed = total weight ÷ weight of snacks in one container

= 54 ÷ 8

= 6.75

Therefore, he will fill 6 containers

Snack left over = total weight - (number of containers × weight of snacks one container will hold)

= 54 - (6 × 8)

= 54 - 48

= 6 ounces

8 0

3 years ago