That would be 4/6, or 2/3 simplified. As a percent, that would be 66%.
I hope this answer helped you! If you have any further questions or concerns, feel free to ask! :)
Answer:
Step-by-step explanation:
Hello!
You have two populations of interest and want to compare them. If you define the study variables as:
X₁: average hourly wages of an employee of the Downtown store.
n₁= 25
X[bar]₁= $9
S₁= $2
X₂: average hourly wages of an employee of the North Mall store.
n₂= 20
X[bar]₂= $8
S₂= $1
Both samples taken are independent, assuming that both populations are normal and that their population variances are equal I'll use the Student's-t statistic with a pooled sample variance to calculate the Confidence interval:
95% CI for μ₁ - μ₂
(X[bar]₁-X[bar]₂) ± 


Sa= 1.64

(9-8)±2.017*
[0.007636;1.9923]
I hope it helps!
The girls are closer. Her feet are 1/2 the distance away from the surface pool, the boys are 3/4 away.
Answer:
I just answer this
x = 4,235294118
Step-by-step explanation: