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Slav-nsk [51]
3 years ago
5

The admission fee for an amusement park is $12 for adults and $6.50 for children. One weekend, 2904 people paid admission for th

e amusement park, and the park made $27,126. How many adults and how many children paid to go to the amusement park that weekend?
Mathematics
1 answer:
morpeh [17]3 years ago
5 0
It seems that you have missed the necessary options for us to answer this question, but anyway, here is the answer.
Based on the given scenario above, the expression would be this: 
<span> a + c = 2904
12a + 6.5c = 27,126
</span>Wherein a is for adult, and c is for children. 
Here is the solution:
a + c = 2904
a = 2904 - c
Next,
12 (2904-c) + 6.5c = 27,126
34,848 - 12c + 6.5c = 27,126
-5.5c = 27,126 - 34, 848
-5.5c = - 7,722 (divide both sides by -5.5)
c = 1,404

Now going back to the first expression:
a + c = 2904
a + 1,404 = 2904
a = 2904 - 1,404
a = 1500

Hope this answer helps.

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Answer:

1000 times

Step-by-step explanation:

Given:

The Sun is roughly 10^2 times as wide as the Earth.

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About how many times as wide as the Sun is KW Sagittarii?

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And as the Star KW Sagittarii is roughly 10^5 times as wide as the Earth, hence the width of the Star = x\times10^{5}

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\frac{x\times10^{5} }{x\times10^{2} }

x canceled by x

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Therefore, Star  KW Sagittarii is 1000 times wider than Sun.

<em>First of all we calculated width of Sun in terms of width of earth and then calculated the width of the Star in terms of earth and for comparison we did simple division that showed that the Star KW Sagittarii is 1000 times wider than the Sun.</em>

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