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3 years ago

9

192 fl oz = ____oz

1 answer:

sleet_krkn [62]3 years ago

6 0

192 fl oz=1.5 fl oz
15pt=30 cups
240fl oz=30 cups
32qt=8 gallons
10qt=40 cups
48c=4qt
72pt=9 gallons
128 fl oz=8 pints

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Estimate the sale price of the item. 60% off a pair of shoes for $51.95

rodikova [14]

$20.78
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7 0

3 years ago

n many population growth problems, there is an upper limit beyond which the population cannot grow. Many scientists agree that t

givi [52]

Answer:

$\frac{dP}{dt} = rP(1 - \frac{P}{K}) = 0.017P(1 - \frac{P}{16})$

Step-by-step explanation:

The logistic function of population growth, that is, the solution of the differential equation is as follows:

$P(t) = \frac{KP_{0}e^{rt}}{K + P_{0}(e^{rt} - 1)}$

We use this equation to find the value of r.

In this problem, we have that:

$K = 16, P_{0} = 2, P(50) = 4$

So we find the value of r.

$P(t) = \frac{KP_{0}e^{rt}}{K + P_{0}(e^{rt} - 1)}$

$4 = \frac{16*2e^{50r}}{16 + 2*(e^{50r} - 1)}$

$4 = \frac{32e^{50r}}{14 + 2e^{50r}}$

$56 + 8e^{50r} = 32e^{50r}}$

$24e^{50r} = 56$

$e^{50r} = 2.33$

Applying ln to both sides of the equality

$50r = 0.8459$

$r = 0.017$

So

The differential equation is

$\frac{dP}{dt} = rP(1 - \frac{P}{K}) = 0.017P(1 - \frac{P}{16})$

3 0

3 years ago

From the top of a tree a bird looks down on a field mouse at an angle of depression of 50 degrees if the field mouse is 40 M fro

Zepler [3.9K]

The tangent function gives the ratio of vertical to horizontal distance in this case.
.. vertical distance = (horizontal distance)*tan(angle of depression)
.. = (40 m)*tan(50°)
.. vertical distance ≈ 47.7 m

6 0

4 years ago

Practice question — Given the trapezoid to the right find the length of legs in the following isosceles trapezoid

ad-work [718]

Given:

A figure of an isosceles trapezoid with bases 18 and 24, and the vertical height is 4.

To find:

The legs of the isosceles trapezoid.

Solution:

Draw another perpendicular and name the vertices as shown in the below figure.

From the figure it is clear that the AEFD is a rectangle. So,

$EF=AD=18$

Since ABCD is an isosceles trapezoid, therefore in triangle ABE and DCF,

$AB=DC$ (Legs of isosceles trapezoid)

$AE=DF$ (Vertical height of isosceles trapezoid)

$m\angle AEB=m\angle DFC$ (Right angle)

$\Delta ABE\cong \Delta DCF$ (HL postulate)

$BE=CF$ (CPCTC)

Now,

$BE+EF+FC=BC$

$2BE+18=24$

$2BE=24-18$

$2BE=6$

$BE=3$

Using Pythagoras theorem in triangle ABE, we get

$Hypotenuse^2=Perpendicular^2+Base^2$

$(AB)^2=(AE)^2+(BE)^2$

$(AB)^2=(4)^2+(3)^2$

$(AB)^2=16+9$

$(AB)^2=25$

Taking square root on both sides, we get

$AB=\pm \sqrt{25}$

$AB=\pm 5$

Side length cannot be negative. So, $AB=5$ .

Therefore, the length of legs in the given isosceles trapezoid is 5 units.

3 0

3 years ago

What is −10x + 1 + 7x = 37

seropon [69]

Answer:

x = -12

Step-by-step explanation:

−10x + 1 + 7x = 37

Combine like terms

-3x+1 = 37

Subtract 1 from each side

-3x +1-1 = 37-1

-3x = 36

Divide each side by -3

-3x/-3 = 36/-3

x = -12

8 0

4 years ago

Read 2 more answers