All categories

3 years ago

What statement best describe pseudoscience

1 answer:

8 0

The correct answer is that it lacks a process for collecting data. Pseudoscience is a claim or practice presented as scientific but does not follows to the scientific method. It is often characterized by contradictory, exaggerated claims and lack of openness to evaluation by other experts. This suggests something being inaccurately portrayed as science.

You might be interested in

the half life of I -137 is 8.07 days. if 24 grams are left after 40.35 days, how many grams were in the original sample?

Ray Of Light [21]

Answer:

768g

Explanation:

We can use to formula $N(A) = N_0(\frac{1}{2})^\frac{t}{t_{1/2}}$ . Here, N(A) is the final amount. N0 is the initial amount. t is the time elapsed, and $t_{1/2}$ is the half life. Plugging in, we get the answer above.

4 0

3 years ago

How many cobalt atoms are in 345 g of cobalt

lilavasa [31]

Answer:

$\boxed {\boxed {\sf About \ 3.53 \ *10^{24}atoms \ Co}}$

Explanation:

To convert from grams to atoms:

Convert grams to moles
Convert moles to grams

1. Convert grams to moles

First, find the molar mass of cobalt using the Periodic Table of Elements.

Cobalt (Co): 58.93319 g/mol

Next, use this mass as a ratio or fraction.

$\frac{58.93319 \ g\ Co}{1 \ mol \ Co}$

Multiply the mass of the given sample (345 grams) by this ratio.

$345 \ g \ Co *\frac{58.93319 \ g\ Co}{1 \ mol \ Co}$

Flip the fraction so the grams of Cobalt will cancel each other out when multiplying.

$345 \ g \ Co *\frac{1 \ mol \ Co}{58.93319 \ g\ Co}$

$345 \ *\frac{1 \ mol \ Co}{58.93319 }$

$\frac{345 \ mol \ Co}{58.93319 } =5.854086636 \ mol \ Co$

2. Convert moles to atoms

Use Avogadro's Number, which tells us the number of units (in this case atoms) in 1 mole.

$6.022 *10^{23} \ atoms/mol$

Use this number as a ratio or fraction.

$\frac{6.022 * 10^{23} \ atoms \ Co}{1 \ mol \ Co}}$

Multiply this ratio by the number of moles we found.

$5.854086636 \ mol \ Co*\frac{6.022 * 10^{23 }\ atoms \ Co}{1 \ mol \ Co}}$

The moles of Cobalt will cancel.

$5.854086636 \ *\frac{6.022 * 10^{23 }\ atoms \ Co}{1 }}$

$5.854086636 \ *{6.022 * 10^{23 }\ atoms \ Co}$

$3.52533097*10^{24} \ atoms \ Co$

3.Round

The original measurement of 345 has 3 significant figures (3, 4, and 5). We must round to 3 sig figs, which is the hundredth place for this measurement.

$3.52533097*10^{24} \ atoms \ Co$

The 5 in the thousandth place tells us to round the 2 to a 3.

$3.53 \ *10^{24}atoms \ Co$

There are about 3.53*10²⁴ atoms of cobalt in 345 grams.

6 0

3 years ago

Suppose you have 1.00 l of an aqueous buffer containing 60.0 mmol acetic acid (pka = 4.76) and 40.0 mmol acetate. what volume of

butalik [34]

Required pH = 4.93
- OH⁻ from NaOH reacts with CH₃COOH giving CH₃COO⁻ and H₂O
- Let the volume of 3.5 M NaOH be x ml
Moles of NaOH = Moles of OH⁻ = Molarity * x ml = 3.5x mmol
- The reaction table for moles is as follows:
CH₃COOH + OH⁻ → CH₃COO⁻ + H₂O
Initial 60 3.5x 40
Change -3.5x -3.5x +3.5x
Final (60-3.5x) 0 (40+3.5x)
- Substitute in Henderson equation and solve for x:
pH = pKa + log $\frac{[CH_{3}COO^-]}{[CH_3COOH]}$
4.93 = 4.76 + log $\frac{(40+3.5x)}{(60-3.5x)}$
0.17 = log $\frac{(40+3.5x)}{(60-3.5x)}$
$\frac{(40+3.5x)}{(60-3.5x)} = 1.479$
x = 5.62 ml NaOH required

4 0

3 years ago

In which of the following sets is the symbol of the element, the number of protons, and the number of electrons given correctly?

Maksim231197 [3]

In, 49 protons, 49 electrons

3 0

4 years ago

Which substance is a mixtureWhich pure substance can be classified as an element

lubasha [3.4K]

Answer:

pure substance : lead ( Pb )

mixture substance : nitrogen ( N )

8 0

3 years ago