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nevsk [136]
3 years ago
6

What statement best describe pseudoscience

Chemistry
1 answer:
Ghella [55]3 years ago
8 0
The correct answer is that it lacks a process for collecting data. Pseudoscience is a claim or practice presented as scientific but does not follows to the scientific method. It is often characterized by contradictory, exaggerated claims and lack of openness to evaluation by other experts. This suggests something being inaccurately portrayed as science.
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the half life of I -137 is 8.07 days. if 24 grams are left after 40.35 days, how many grams were in the original sample?
Ray Of Light [21]

Answer:

768g

Explanation:

We can use to formula N(A) = N_0(\frac{1}{2})^\frac{t}{t_{1/2}} . Here, N(A) is the final amount. N0 is the initial amount. t is the time elapsed, and t_{1/2} is the half life. Plugging in, we get the answer above.

4 0
3 years ago
How many cobalt atoms are in 345 g of cobalt
lilavasa [31]

Answer:

\boxed {\boxed {\sf About \ 3.53 \ *10^{24}atoms \ Co}}

Explanation:

To convert from grams to atoms:

  1. Convert grams to moles
  2. Convert moles to grams

1. <u>Convert grams to moles</u>

First, find the molar mass of cobalt using the Periodic Table of Elements.

  • Cobalt (Co): 58.93319 g/mol

Next, use this mass as a ratio or fraction.

\frac{58.93319 \ g\ Co}{1 \ mol \ Co}

Multiply the mass of the given sample (345 grams) by this ratio.

345 \ g \ Co *\frac{58.93319 \ g\ Co}{1 \ mol \ Co}

Flip the fraction so the grams of Cobalt will cancel each other out when multiplying.

345 \ g \ Co *\frac{1 \ mol \ Co}{58.93319 \ g\ Co}

345 \  *\frac{1 \ mol \ Co}{58.93319 }

\frac{345 \ mol \ Co}{58.93319 } =5.854086636 \ mol \ Co

2. <u>Convert moles to atoms</u>

Use Avogadro's Number, which tells us the number of units (in this case atoms) in 1 mole.

  • 6.022 *10^{23} \ atoms/mol

Use this number as a ratio or fraction.

\frac{6.022 * 10^{23} \ atoms \ Co}{1 \ mol \ Co}}

Multiply this ratio by the number of moles we found.

5.854086636 \ mol \ Co*\frac{6.022 * 10^{23 }\ atoms \ Co}{1 \ mol \ Co}}

The moles of Cobalt will cancel.

5.854086636 \ *\frac{6.022 * 10^{23 }\ atoms \ Co}{1 }}

5.854086636 \ *{6.022 * 10^{23 }\ atoms \ Co}

3.52533097*10^{24} \ atoms \ Co

3.<u>Round</u>

The original measurement of 345 has 3 significant figures (3, 4, and 5). We must round to 3 sig figs, which is the hundredth place for this measurement.

3.52533097*10^{24} \ atoms \ Co

The 5 in the thousandth place tells us to round the 2 to a 3.

3.53 \ *10^{24}atoms \ Co

There are about <u>3.53*10²⁴ atoms of cobalt in 345 grams.</u>

6 0
3 years ago
Suppose you have 1.00 l of an aqueous buffer containing 60.0 mmol acetic acid (pka = 4.76) and 40.0 mmol acetate. what volume of
butalik [34]
Required pH = 4.93
- OH⁻ from NaOH reacts with CH₃COOH giving CH₃COO⁻ and H₂O 
- Let the volume of 3.5 M NaOH be x ml
Moles of NaOH = Moles of OH⁻ = Molarity * x ml = 3.5x mmol
- The reaction table for moles is as follows:
                   CH₃COOH + OH⁻ →  CH₃COO⁻ + H₂O
Initial               60             3.5x          40
Change         -3.5x         -3.5x         +3.5x
Final            (60-3.5x)       0           (40+3.5x)
- Substitute in Henderson equation and solve for x:
pH = pKa + log \frac{[CH_{3}COO^-]}{[CH_3COOH]}
4.93 = 4.76 + log \frac{(40+3.5x)}{(60-3.5x)}
0.17 = log \frac{(40+3.5x)}{(60-3.5x)}
\frac{(40+3.5x)}{(60-3.5x)} = 1.479
x = 5.62 ml NaOH required 
4 0
3 years ago
In which of the following sets is the symbol of the element, the number of protons, and the number of electrons given correctly?
Maksim231197 [3]

In, 49 protons, 49 electrons

3 0
4 years ago
Which substance is a mixtureWhich pure substance can be classified as an element
lubasha [3.4K]

Answer:

pure substance : lead ( Pb )

mixture substance : nitrogen ( N )

8 0
3 years ago
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