Answer:
The 2 would be placed in front of the reactant Na and in front of the product NaCl
2Na + Cl2 = 2NaCl
Explanation:
This is because the ratio of elements needs to be balanced on both sides.
On the reactants side, there are 2 Na molecules and 2 Cl molecules
On the products side, there are 2 Na molecules and 2 Cl molecules
So, now the equation is balanced
Answer:
Mass of Na₂CrO₄ = 5.75 g
Explanation:
First of all we will write the balance chemical equation.
2AgNO₃ + Na₂CrO₄ → Ag₂CrO₄ + 2NaNO₃
Now we will calculate the moles of AgNO₃.
Number of moles = mass / molar mass
Molar mass of AgNO₃ = 107.87 + 14 + 3× 16 = 169.87 g/mol
Number of moles = mass / molar mass
Number of moles = 12.1 g / 169.87 g/mol = 0.071 mol
Now we will compare the moles of AgNO₃ and Na₂CrO₄ from balance chemical equation.
AgNO₃ : Na₂CrO₄
2 : 1
0.071 : 1/2× 0.071 = 0.0355
Now we will calculate the mass of Na₂CrO₄.
Molar mass of Na₂CrO₄ = 23×2 + 52 + 16×4 = 162 g/mol
Mass of Na₂CrO₄ = number of moles × molar mass
Mass of Na₂CrO₄ = 0.0355 mol × 162 g/mol
Mass of Na₂CrO₄ = 5.75 g
Answer:
C20 H14 O2
Explanation:
Remark
This is a sample, which the question does not say and should. It is a fraction of 1 mole. So what you have to do is multiply the numbers given by x and equate it to 286.28
Equation
150,86* x + 8.86*x + 20.1*x = 286.28
179.8x = 286.28
x = 286.26/179.8
x = 1.592
Now multiply the given numbers by 1.592
150.86 * 1.592 = 240.58
8.85 * 1.592 = 14.1
20.1 * 1.592 = 32
Rounding you get
240/12 = 20
14.1/1 = 14
32/16 = 2
C20 H14 O2
John Dalton was the first scientist
To find the wavelength of an electromagnetic wave for the given frequency can be determined by using the formulaSpeed=Wavelength x FrequencyWavelength=Speed/FrequencyGenerally Speed of the electromagnetic wave is 3x10^8 m/sBy substituting the values Wavelength=3x10^8 m/s / 2.63x10^12 s^-1Wavelength=1.14 x 10^-4 metres
