Answer:
The number of distinct arrangements is <em>12600</em><em>.</em>
Step-by-step explanation:
This is a permutation type of question and therefore the number of distinguishable permutations is:
n!/(n₁! n₂! n₃! ... nₓ!)
where
- n₁, n₂, n₃ ... is the number of arrangements for each object
- n is the number of objects
- nₓ is the number of arrangements for the last object
In this case
- n₁ is the identical copies of Hamlet
- n₂ is the identical copies of Macbeth
- n₃ is the identical copies of Romeo and Juliet
- nₓ = n₄ is the one copy of Midsummer's Night Dream
Therefore,
<em>Number of distinct arrangements = 10!/(4! × 3! × 2! × 1!)</em>
<em> = </em><em>12600 ways</em>
<em />
Thus, the number of distinct arrangements is <em>12600</em><em>.</em>
Condition (A) P(B/A) = y is true.
<h3>
What is probability?</h3>
- Probability is an area of mathematics that deals with numerical descriptions of how probable an event is to occur or how likely a statement is to be true.
To find the true condition:
If two events are independent, then:
Use formulas for conditional probabilities:
- Pr(A/B) = Pr(A∩B) / Pr(B)
- Pr(B/A) = Pr(B∩A) / Pr(A)
For independent events these formulas will be:
- Pr(A/B) = Pr(A∩B) / Pr(B) = Pr(A) . Pr(B) / Pr(B) = Pr(A)
- Pr(B/A) = Pr(B∩A) / Pr(A) = Pr(B) . Pr(A) / Pr(A) = Pr(B)
Now in your case, Pr(A) = x and Pr(B) = y.
- Pr(A/B) = x, Pr(B/A) = y, Pr(A∩B) = x.y
Therefore, condition (A) P(B/A) = y is true.
Know more about probability here:
brainly.com/question/25870256
#SPJ4
The complete question is given below:
The probability of event A is x, and the probability of event B is y. If the two events are independent, which of these conditions must be true?
a. P(B|A) = y
b. P(A|B) = y
c. P(B|A) = x
d. P(A and B) = x + y
e. P(A and B) = x/y
1/6 = 0.1666, the last number repeating to infinity, or a repeating decimal.
Hope helps!-Aparri
<em>Answer:</em>
<em>-24, 48, -96</em>
<em>Step-by-step explanation:</em>
<em>The number before multiplies by -2.</em>
<em>3*-2=-6</em>
<em>and so on. </em>
<em>Hope this helps. Have a nice day.</em>