It is c tell me it is right
Answer:
(x, y) = (0, -14), (2, -8), (3, -5)
Step-by-step explanation:
Put the given values into the equation and solve.
<u>x = 0</u>
y = 3·0 -14 = -14
<u>y = -8</u>
-8 = 3x -14
6 = 3x . . . . . . add 14
2 = x . . . . . . . divide by 3
<u>x = 3</u>
y = 3·3 -14 = -5
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The ordered pairs in your table are ...
(x, y) = (0, -14), (2, -8), (3, -5)
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<em>Comment on the approach</em>
In this problem, you are only asked for one x-value for a given y-value. If there were more, you would solve the equation generically (x = (y+14)/3) and use that to compute the desired values of x.
area = (l)(w)(h)
24 = 4(3 + b)
24 = 12 + 4b
-12 on both sides
12 = 4b
/4 on both sides
b = 3 inches
Substitute b = 3 inches in width
3 + b
3 + 3 = 6 inches
Answer:
width = 6 inches
50=3x+b. you never specify the variable that replaces b
Answer:
1.4 times as high
Step-by-step explanation:
Now here we have to compare the both final velocities by using the formula independent of time. As we know,
2aS = V(f)2 - V(i)2
Both balls are dropped from certain height, so V(i) = 0 m/s for both balls
So, 2aS = V(f)2 for both balls.
Now if we compare both velocities
Equation for first ball
2aS(1) = V(1)2
Equation for second ball
2aS(2) = V(2)2
Comparing both equations
2aS(1)/2aS(2) = V(1)2/V(2)2
as we now S(1) = 5m and S(2) = 10m, also acceleration a = g, because acceleration due to gravity is acting on the balls. So,
2(9.8) x 5/2(9.8) x 10 = V(1)2/V(2)2
after simplifying,
1/2 = V(1)2/V(2)2
V(2)^2 = 2V(1)^2
By taking square root on both sides,
V(2) = 1.4V(1)