Question

PLEASE help with these math questions

Answer 1

Pythagorean theorem: a² + b² = c²
a = long leg
b = short leg
c = hypotenuse

graph can form a right triangle:
JK: a = 7 - 3 = 4 ; b = 5 - 3 = 2 
⇒ 4² + 2² = c² ⇒ 16 + 4 = 20 ; c = √20 = 4.47 or 4.5 units

VW: a = 6 - (-2) = 6 + 2 = 8 ; b = -3 - (+4) = 7
⇒ 8² + 7² = c² ⇒ 64 + 49 = 113 ; c = √113 = 10.63 units

EG: a = 7 - (-2) = 7 + 2 = 9 ; b = 9 - 1 = 8
⇒ 9² + 8² = c² ⇒ 81 + 64 =  145 ; c = √145 = 12.04 units

EG: a = -1 - 6 = 7 ; b = 2 - (-2) = 2 + 2 = 4
⇒ 7² + 4² = c² ⇒ 49 + 16 = 65 ; c = √65 = 8.06 units

Trapezoid: Rectangle and right triangle.

Rectangle = 1 side of the width is the long leg of the right triangle.

a = 8 - 2 = 6 ; b = 12 - 9 = 3
6² + 3² = c² ; 36 + 9 = 45 ; c = √45 = 6.71 units

upper base:CD:  9 - 2 = 7
lower base: BA: 12 - 2 = 10
side: DA: 8 - 2 = 6
side: CB: 6.71

Perimeter = 7 + 10 + 6 + 6.71 = 29.71 units

Answer 2

The first one is just some simple application of Pythagora's theorem.

Since you go up -2 (no negative lengths), and across 4. You can apply the theorem to get:
2^2 + 4^2 = x^2
x = 4.4721
x = 4.5

I won't answer all of these for you, if you need more help just say please.