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Vikentia [17]
3 years ago
12

The graph of y=1/x is shown below. Draw the graph of its inverse.

Mathematics
2 answers:
NeTakaya3 years ago
5 0

Answer:

The graph of the inverse of function would be same.

Step-by-step explanation:

We have been given graph of function y=\frac{1}{x}. We are asked to graph the inverse of our given function.

To find the inverse of a function, we will interchange the x and y variables and solve for y.

Upon interchanging variables, we will get:

x=\frac{1}{y}

Upon multiplying both sides of our equation by y, we will get:

x*y=\frac{1}{y}*y

x*y=1

Now, we will divide both sides of our equation by x as:

\frac{x*y}{x}=\frac{1}{x}

y=\frac{1}{x}

Since the inverse of our given function is same as function y=\frac{1}{x}, therefore, the graph of the inverse of function would be same.

lord [1]3 years ago
4 0
Y=1/x  solve for x

x=1/y  now reverse lables...

y=1/x  

Yes that is the same equation you started with.  What that means is the the inverse function in this case produces the same exact graph :)
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Step-by-step explanation:

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Rich also has £400 pounds invest 3% compound interest . How many years does he need to invest the money to get at least £475
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Answer: 6 years

Step-by-step explanation:

Formula to calculate compound amount: A=P(1+r)^t, where P= Principal , r=rate of interest, t= time

Given: P = £400, r = 3% = 0.03 , A= 475

Required equation: 400(1+0.03)^t\geq475

400(1.03)^t\geq475\\\\\Rightarrow\ (1.03)^t\geq\dfrac{475}{400}\\\\\Rightarrow\ (1.03)^t\geq1.1875

Taking log on both sides , we get

t \log 1.03\geq\log1.1875\\\\\Rightarrow\ t(0.0128372)\geq(0.0746336)\\\\\Rightarrow\ t\geq\dfrac{0.0746336}{0.0128372}=5.81385\approx6

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2 years ago
Identify the interval on which the quadratic function is positive.
Alenkasestr [34]

Answer:

\textsf{1. \quad Solution:  $1 < x < 4$,\quad  Interval notation:  $(1, 4)$}

\textsf{2. \quad Solution:  $-2 < x < 4$,\quad  Interval notation:  $(-2, 4)$}

Step-by-step explanation:

<h3><u>Question 1</u></h3>

The intervals on which a <u>quadratic function</u> is positive are those intervals where the function is above the x-axis, i.e. where y > 0.

The zeros of the <u>quadratic function</u> are the points at which the parabola crosses the x-axis.  

As the given <u>quadratic function</u> has a negative leading coefficient, the parabola opens downwards.   Therefore, the interval on which y > 0 is between the zeros.

To find the zeros of the given <u>quadratic function</u>, substitute y = 0 and factor:

\begin{aligned}y&= 0\\\implies -7x^2+35x-28& = 0\\-7(x^2-5x+4)& = 0\\x^2-5x+4& = 0\\x^2-x-4x+4& = 0\\x(x-1)-4(x-1)&= 0\\(x-1)(x-4)& = 0\end{aligned}

Apply the <u>zero-product property</u>:

\implies x-1=0 \implies x=1

\implies x-4=0 \implies x=4

Therefore, the interval on which the function is positive is:

  • Solution:  1 < x < 4
  • Interval notation:  (1, 4)

<h3><u>Question 2</u></h3>

The intervals on which a <u>quadratic function</u> is negative are those intervals where the function is below the x-axis, i.e. where y < 0.

The zeros of the <u>quadratic function</u> are the points at which the parabola crosses the x-axis.  

As the given <u>quadratic function</u> has a positive leading coefficient, the parabola opens upwards.   Therefore, the interval on which y < 0 is between the zeros.

To find the zeros of the given <u>quadratic function</u>, substitute y = 0 and factor:

\begin{aligned}y&= 0\\\implies 2x^2-4x-16& = 0\\2(x^2-2x-8)& = 0\\x^2-2x-8& = 0\\x^2-4x+2-8& = 0\\x(x-4)+2(x-4)&= 0\\(x+2)(x-4)& = 0\end{aligned}

Apply the <u>zero-product property</u>:

\implies x+2=0 \implies x=-2

\implies x-4=0 \implies x=4

Therefore, the interval on which the function is negative is:

  • Solution:  -2 < x < 4
  • Interval notation:  (-2, 4)
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