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3 years ago

Write an algebraic expression for 15 decreased by twice a number

2 answers:

6 0

An algebraic expression is, obviously, an expression with a variable.

"A number" would represent a variable, which, in this case, we'll use y.

So, 15 decreased by twice x.
15 - y x 2 =

I hope this helped :)

sineoko [7]3 years ago

6 0

15-2x= that would be the algebraic equation. Remember that decrease usually means minus. A number is always represented by a variable, and then anything that by is usually a multiplication or division depending on how its stated.

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The equation y=0.002x-0.20 can be used to determine the approximate profit,y in dollars,of producing x items.solve for x. How ma

lakkis [162]

Answer:

1966600 items must be produced in other to profit $3933

Step-by-step explanation:

from the equation y = 0.002x -0.20

where y is the profit in dollars

and x is the number of items

then to get the number of item to be produced in other to profit $3933 ?

will be by substituting $3933 for y in the equation and solving for x,

3933 = 0.002x - 0.20

Firstly you will add 0.20 to both sides, which will be

3933 + 0.20 = 0.002x - 0.20 + 0.20

3933.20 = 0.002x

then we will divide both sides by 0.002

3933.20 / 0.002 = 0.002x / 0.002

therefore, x = 1966600

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3 years ago

Find the solution <br> -1.2x-8.2>-9.7

andriy [413]

The solution to the equation is x < 1.25

3 0

2 years ago

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Katen [24]

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3 years ago

Read 2 more answers

write a polynomial function of least degree with integral coefficients that has the given zeros. -(1/3), -i

inessss [21]

Answer:

$f(x)=3x^3+x^2+3x+1$

Step-by-step explanation:

If a real number $-\frac{1}{3}$ is a zero of polynomial function, then

$x-\left(-\dfrac{1}{3}\right)=x+\dfrac{1}{3}$

is the factor of this function.

If a complex number $-i$ is a xero of the polynomial function, then the complex number $i$ is also a zero of this function and

$x-(-i)=x+i\ \text{ and }\ x-i$

are two factors of this function.

So, the function of least degree is

$f(x)=\left(x+\dfrac{1}{3}\right)(x+i)(x-i)=\left(x+\dfrac{1}{3}\right)(x^2-i^2)=\\ \\ =\left(x+\dfrac{1}{3}\right)(x^2+1)=\dfrac{1}{3}(3x+1)(x^2+1)=\dfrac{1}{3}(3x^3+x^2+3x+1)$

If the polynomial function must be with integer coefficients, then it has a form

$f(x)=3x^3+x^2+3x+1$

4 0

3 years ago

What is the base of a triangle with an area of 207 square inches and a height of 18 inches

White raven [17]

Answer: 23 in

Step-by-Step Explanation:

Height (h) = 18 in
Base (b) = ?
Area (A) = 207 sq. in

We know,
Area of a Triangle = 1/2 * b * h

Therefore,
1/2 * b * h = 207
1/2 * b * 18 = 207
b * 9 = 207
9b = 207
b = 207/9
=> b = 23

Base (b) = 23 in

4 0

1 year ago