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4 years ago

Worth 20 points, please help!

Mathematics

1 answer:

serg [7]4 years ago

5 0

Answer: 3

Step-by-step explanation:

To solve this problem you must apply the proccedure shown below:

1. Find the prime factorization of 27:

$27=3*3*3$ or $27=3^{3}$

2. The index of the radical is 3, therefore, you have rewrite it as following:

$\sqrt[3]{27}=\sqrt[3]{3^{3}}=3^{\frac{3}{3}}=3^{1}=3$

3. Therefore, as you can see, the answer is 3.

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(1. - 2.9), (3, - 1.9), (3, 3), (1, 2)

bezimeni [28]

In my opinion i think it’s D.parallelogram

5 0

3 years ago

Which graph below represents a functional relationship? A. 10 10 8 8 6 6 4 2 2 X 10864 6 8 10 10 8 6 4 4 6 8 10 -21 4 -61 -8 -8

Anestetic [448]

Answer:

Graph (C)

Step-by-step explanation:

To find whether the graph\table represents a relationship or a function we have to analyze the input-output values given.

Graph A.

In this graph for every input value (x-value) there are two output values (y-values).

For x = -2, y = -2, 2

So the graph doesn't represent a function.

Graph B.

For every x value there are two y-values

For x = -5, y = -3, 3

So the graph doesn't represent a function.

Graph C.

For every input value there is a different y-value.

Therefore, graph represents a function.

Graph D.

In this graph for x = 3, y = 1, 2, 3, 4

For one value of x, there are four values of y.

Therefore, graph doesn't show the relationship.

4 0

3 years ago

What are all of the real roots of the following polynomial? f(x) = x4 - 13x2 + 36

GREYUIT [131]

ANSWER

A. -3, -2, 2, and 3

EXPLANATION

The given polynomial function is,

$f(x) = {x}^{4} - 13 {x}^{2} + 36$

To find the real roots, we equate the function to zero to obtain;

${x}^{4} - 13 {x}^{2} + 36 = 0$

We can solve this equation as a quadratic equation in
${x}^{2}.$

Thus we rewrite the equation as,

$({x}^{2})^{2} - 13 {x}^{2} + 36 = 0$

We split the middle term to get,

$({x}^{2})^{2} - 9 {x}^{2} - 4 {x}^{2} + 36 = 0.$

We factor to get,

${x}^{2} ( {x}^{2} - 9) - 4( {x}^{2} - 9) = 0$

We factor to get,

$( {x}^{2} - 9)( {x}^{2} - 4) = 0$

Either

${x}^{2} - 9 = 0$
or

${x}^{2} - 4 = 0$

$x = \pm \sqrt{9} \: or \: x = \pm \sqrt{4}$
$x = \pm3 \: or \: x = \pm2$

$x=-3,-2,2,3$

The correct answer is A

5 0

4 years ago

Read 2 more answers

Line p represents the rule x and y are equal

MArishka [77]

Ok so then line p is the equation y=x

is that all you needed?

4 0

4 years ago

The diagram below represents a street intersection. The dashed lines are new streets that are being proposed. If the turn repres

Katarina [22]

Answer:

Step-by-step explanation:

5 0

3 years ago