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lys-0071 [83]
3 years ago
15

How can a community be " held hostage" by a team?

Mathematics
2 answers:
mixas84 [53]3 years ago
4 0

Answer:

by force I suppose

Step-by-step explanation:

how is this mathematics?

Simora [160]3 years ago
3 0
Oh yeah sweetie I’m gonna be there for you
You might be interested in
3. Which graph best represents the solution to the following system? (1 point)<br> (5x – 2y &lt;10
Step2247 [10]

Answer:

The graph in the attached figure

Step-by-step explanation:

The complete question is

Which graph best represents the solution to the following system?

5x - 2y < (less than or equal to) 10

x + y < 5

we have

5x-2y\leq 10 ----> inequality A

isolate the variable y

Adds 2y both sides

5x \leq 10+2y

Subtract 10 both sides

5x-10 \leq 2y

Divide by 2 both sides

2.5x-5 \leq y

Rewrite

y \geq 2.5x-5

The solution of the inequality A is the shaded area above the solid line

The equation of the solid line is y=2.5x-5

The slope of the solid line is positive m=2.5

The y-intercept of the solid line is (0,-5)

The x-intercept of the solid line is (2,0)

x+y < 5 -----> inequality B

Isolate the variable y

Subtract x both sides

y < -x+5

The solution of the inequality B is the shaded area below the dashed line

The equation of the dashed line is y=-x+5

The slope of the dashed line is negative m=-1

The y-intercept of the dashed line is (0,5)

The x-intercept of the dashed line is (5,0)

using a graphing tool

The solution of the system of inequalities is the shaded area between the solid line and the dashed line

see the attached figure

7 0
3 years ago
H = {(2, 5), (3, 5), (4, 5), (5, 5), (6, 5)} Is H a function and why?
Lorico [155]

Answer:

h is a function

Step-by-step explanation:i know that h is a function i just dont know why

7 0
3 years ago
I need help finding the area
aniked [119]
<h3>Given :</h3>
  • Base of triangle = 7 yd
  • Height of triangle = 10 yd

\\  \\

<h3>To find:</h3>
  • Area of triangle

\\  \\

We know:-

When base and height of triangle is given we use this formula:

\bigstar \boxed{ \rm Area \: of \: triangle =  \frac{base \times height}{2} }

\\  \\

So:-

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{base \times height}{2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 10}{2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 5 \times2 }{2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 5 \times\cancel2 }{\cancel2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 5 \times1 }{1}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =7 \times 5

\\  \\

\dashrightarrow \bf \: Area \: of \: triangle =35 {yd}^{2}  \\

\\  \\

\therefore  \underline{\textsf{ \textbf {\: Area \: of \: triangle = \red{35}}} {  \red{\bf{yd} }^{ \red2} }}

\\  \\

<h3>know more :-</h3>

\small\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf \small{Formulas\:of\:Areas:-}}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Base\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Base\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}\end{gathered}\end{gathered}]

7 0
2 years ago
Is there an error in this statement If x2 = 25, then x = 5.
katen-ka-za [31]
Yes there is an error in this statement.

because x^2 = 25 
so x = 5...this is one condition

Another condition is x = -5
(-5)^2 = 25 (this is also true)
7 0
3 years ago
Read 2 more answers
I really need help with these questions, 5 STARS AND BRAINLIEST FOR WHOEVER HAS THE BEET ANSWER!!
zvonat [6]
1) y=(7/2)x-2.
Slope is the coefficient of x, that is 7/2

Intercept x is the value of x when y = 0 ==> 0=(7/2) X - 2==> 7/2x=2 &x=4/7
so intercept  x, (4/7,0)

Intercept y is the value of y when x=0 ==> y= (7/2).(0) - 2 ==> y = 2 
and so intercept  y, (0,-2)

Now you will follow the same logic to find the are same questions

2) y= -6x + 3 ==>Slope= -6, Intercept x =1/2 & intercept y=3

3) y=-5 has a slope 0 (it doesn't exist). The graph is a line // to x-axis at y=-5

4)y=(6/5)x + 1:==>Slope= -5/6, Intercept x =-5/6 & intercept y=1

5) y=(1/4)x + 2 ==>Slope= 1/4, Intercept x =-8  & intercept y=2

6) x=5, this ligne is // to y axis at x=-5


 
5 0
3 years ago
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