Ask question

Ask question

All categories

Zigmanuir [339]

3 years ago

12

Consider the video you just watched. Suppose we replace the original launcher with one that fires the ball upward at twice the s

peed. We make no other changes. How far behind the cart will the ball land, compared to the distance in the original experiment?

1 answer:

Roman55 [17]3 years ago

7 0

Answer:

height of the ball + distance of the ball

Step-by-step explanation:

if we calculate ^it we can find it

You might be interested in

Kyle wants to buy a hat for $5.75, a T-shirt for $7.65, and a keychain for $3.15. He has $16. Does

astra-53 [7]

He doesn’t have enough for all 3

6 0

3 years ago

Read 2 more answers

Reduce the following fraction 25/55<br><br><br> Pls help quickly

Lina20 [59]

Answer:

5/11

Step-by-step explanation:

5 0

3 years ago

Two vectors and have the components, in meters, ax = 6.91, ay = 1.45, bx = 2.45, by = 7.02. (a) find the angle between the direc

White raven [17]

We are given
ax = 6.91
ay = 1.45

bx = 2.45
by = 7.02

So,
tan a→ = 1.45/6.91 = 0.2098 = ma
tan b→ = 7.02/2.45 = 2.8653 = mb

To get the angle between the two
tan θ = (mb - ma)/(1 + ma mb)
tan θ = (2.8653 - 0.2098) / (1 + (2.8653) (0.2098) )
θ = 58.91°
The x component is
x = 8.28 cos 58.91 = 4.28 m
The y component is
y = 8.28 sin 58.91 = 7.09 m

8 0

4 years ago

Please help me<br> Evaluate 7+2^3<br> Answer:________

Natalija [7]

Answer:

9^...................

7 0

3 years ago

Read 2 more answers

(2x+3)(4x-1)<8x^(2)+1

Sidana [21]

Answer: $x$

Step-by-step explanation:

$(2x+3)(4x-1)$

Begin by multiplying parentheses.

$(2x*4x)+(2x*-1)+(3*4x)+(3*-1)$

$(8x^2)+(-2x)+(12x)+(-3)$

$8x^2-2x+12x-3$

Subtract $8x^2$

$8x^2-2x+12x-3+(-8x^2)$

$-2x+12x-3$

Add 3

$-2x+12x-3+3$

$-2x+12x$

Combine like terms;

$10x$

Divide by 10

$x$

Simplify;

$x$

8 0

3 years ago