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Zigmanuir [339]
2 years ago
12

Consider the video you just watched. Suppose we replace the original launcher with one that fires the ball upward at twice the s

peed. We make no other changes. How far behind the cart will the ball land, compared to the distance in the original experiment?
Mathematics
1 answer:
Roman55 [17]2 years ago
7 0

Answer:

height of the ball + distance of the ball

Step-by-step explanation:

if we calculate ^it we can find it

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Since you didn't give me any choices I can tell you that c is ANY ODD NUMBER THAT EXISTS.

Step-by-step explanation:

im smart ツ

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2 years ago
Please help me it’s due today and idk math .
Ulleksa [173]

Answer:

you need to ask one bye one. easyer for us

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A mermaid is swimming at sea level when a human comes by. She dives underwater at a rate of 8 meters per second. She continues t
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4 0
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. $7.45 + ‐$24.45 + $74.17 + ‐$76.52
lisov135 [29]

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$-19.35 or -19.35 aprox

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
15x-7=2+12x I need help with this
Amanda [17]

Answer:

\huge{ \boxed{ \bold{ \tt{x = 3}}}}

<h3>♁ Question : Solve for x</h3>
  • 15x - 7 = 2 + 12x

<h3>♁ Step - by - step explanation</h3>
  • \text{15x - 7 = 2 + 12x}

Move 12x to L.H.S ( Left Hand Side ) and change it's sign

➛\sf{15x - 12x - 7 = 2}

Move 7 to R.H.S ( Right Hand Side) and change it's sign

➛\sf{15x - 12x = 2 + 7}

Subtract 12x from 15x

Remember that only coefficients of like terms can be added or subtracted.

➛\sf{3x = 2 + 7}

Add the numbers : 2 and 7

➛\sf{3x = 9}

Divide both sides by 3

➛ \sf{ \frac{3x}{3}  =  \frac{9}{3}}

➛ \boxed{ \bold{ \sf{x = 3}}}

The value of x is \boxed{ \sf{3}}

✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄

☄ Now, let's check whether the value of x is 3 or not!

<h3>☥ Verification :</h3>

\sf{15x - 7 = 2 + 12x}

\dashrightarrow{ \sf{15 \times 3 - 7 = 2 + 12 \times 3}}

\dashrightarrow{ \sf{45 - 7 = 2 + 36}}

\dashrightarrow{ \sf{38 = 38}}

L.H.S = R.H.S ( Hence , the value of x is 3 ).

✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄

<h3>✒ Rules for solving an equation :</h3>
  • If an equation contains fractions ,multiply each term by the L.C.M of denominators.
  • Remove the brackets , if any.
  • Collect the terms with the variable to the left hand side and constant terms to the right hand side by changing their sign ' + ' into ' - ' and ' - ' into ' + ' .
  • Simplify and get the single term on each side.
  • Divide each side by the coefficient of variable and then get the value of variable.

Hope I helped!

Have a wonderful time ! ツ

~TheAnimeGirl

5 0
2 years ago
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