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Darya [45]
4 years ago
7

There are 30 students in Mr. Baker’s music class. One day, 12 students played the recorder. What was the ratio of students who p

layed the recorder to students who did not play the recorder? Question 2 options: 12 : 30 30 : 12 12 : 18 18 : 12
Mathematics
1 answer:
IgorLugansk [536]4 years ago
5 0

Answer:

12:30

Step-by-step explanation:

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185g <br> 2:3 what is the mass for yogurt
Wewaii [24]
If the full questions as below;

A dessert has both fruit and yogurt inside. altogether,the mass of the dessert is 185g. the ratio of the mass of fruit to the mass of yogurt is 2:3. what is the mass of yogurt?
total dessert 3:3
since the ratio of the mass of fruit is 2:3
the remaining would be
the ratio of the mass of yogurt which is 1:3
then the answer is:
the mass of yogurt would be one 3rd of the total dessert
185g÷3= 61.66g

cool? :)
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3 years ago
2x=y+3 in slope intercept form
Shkiper50 [21]

Answer:

y=2x-3

Step-by-step explanation:

8 0
3 years ago
Try to get the answer and explain how u got it​
lubasha [3.4K]

Answer:

I think it's a

Step-by-step explanation:

because obviously the pyramid has a square base and triangles around it, which rules out c, and if you try and fold them together in your head

3 0
3 years ago
Read 2 more answers
PLEASE HELP!!
erik [133]
2.=c.\\\\2\sin4x\cos4x=2\sin(2\cdot4x)=2\sin8x\\\\Used:\\\sin2\alpha=2\sin\alpha\cos\alpha

1.=b.\\\\\csc x-\sin x=\dfrac{1}{\sin x}-\dfrac{\sin^2x}{\sin x}=\dfrac{1-\sin^2x}{\sin x}=\dfrac{\cos^2x}{\sin x}\\\\=\dfrac{\cos x\cos x}{\sin x}=\cos x\cdot\dfrac{\cos x}{\sin x}=\cos x\cot x\\\\Used:\\\csc x=\dfrac{1}{\sin x}\\\\\sin^2x+\cos^2x=1\to\cos^2x=1-\sin^2x\\\\\cot x=\dfrac{\cos x}{\sin x}

3.=a.\\\\\dfrac{\sin x-1}{\sin x+1}=\dfrac{\sin x-1}{\sin x+1}\cdot\dfrac{\sin x+1}{\sin x+1}=\dfrac{\sin^2x-1^2}{(\sin x+1)^2}=\dfrac{\sin^2x-1}{(\sin x+1)^2}\\\\=\dfrac{-(1-\sin^2x)}{(\sin x+1)^2}=\dfrac{-\cos^2x}{(\sin x+1)^2}\\\\Used:\\(a-b)(a+b)=a^2-b^2\\\\\sin^2x+\cos^2x=1\to \cos^2x=1-\sin^2x
8 0
3 years ago
Write the equation of the given circle. center (1, -5) radius of 10
Ksenya-84 [330]
The circle equation is in the format (x – h)2 + (y – k)2= r2, with the center being at the point (h, k) and the radius being "r". 

Therefore (x – 1)2 + (y +5)2= 102
x2 + y2 + 1 - 2x + 25 + 10y = 100
x2 + y2 - 2x + 10y = 74
6 0
3 years ago
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