Did you mean to answer someone else’s question?
Answer:
Follows are the solution to this question:
Step-by-step explanation:
Given:
All points are on the graph including its quadratic function, in order to install their coordinates to values of x and y with the following values:
Inserting the coordinates of the first point
Inserting the coordinates of the second point
Inserting the coordinates of the third point
For the answer to the question above,
The slope of the line of the line is calculated through the equation,
m = (y2 - y1) / (x2 - x1)
Using the first two points in the given,
m = (-7 - 9) / (-12 - 8) = 4/5
The line parallel to this has also a slope of 4/5. Through the point-slope form, the equation of the second line is,
y - -15 = (4/5)(x - -5)
Simplifying gives the answer of,
y = (4/5)x -11
Eliminating the fraction,
5y = 4x - 55
I hope my answer helped you.
Hi
(6-d)(d²-5+3d) = 6d²-30+18d-d³+5d-3d² = -d³+6d²-3d²+18d+5d-30
(6-d)(d²-5+3d) = -d³+3d²+23d-30
Answer: -d³+3d²+23d-30
