I believe the answer is 2x+2y= 20-21 or 2x+2y= -1. Think about Standard Form= Ax+By= C
The answer is b I did this before
Answer:
B. 4 imaginary; 1 real
Step-by-step explanation:
Given the polynomial:
x^5 + 7*x^4 + 2*x^3 + 14*x^2 + x + 7
it can be reordered as follows
(x^5 + 2*x^3 + x ) + (7*x^4 + 14*x^2 + 7)
Taking greatest common factor at each parenthesis
x*(x^4 + 2*x^2 + 1) + 7*(x^4 + 2*x^2 + 1)
Taking again the greatest common factor
(x + 7)*(x^4 + 2*x^2 + 1)
Replacing x^2 = y in the second parenthesis
(x + 7)*(y^2 + 2*y + 1)
(x + 7)*(y + 1)^2
Coming back to x variable
(x + 7)*(x^2 + 1)^2
There are two options to find the roots
(x + 7) = 0
or
(x^2 + 1)^2 = 0 which is the same that (x^2 + 1) = 0
In the former case, x = -7 is the real root. In the latter, (x^2 + 1) = 0 has no real solution. Therefore, there is only 1 real root in the polynomial.
Answer:
Step-by-step explanation:
x->5
y->2
x*5+y*2=60
if x=10——> y=5 ——> 50+10=60
if x=8——> y=10——> 40+20=60
if x=6——> y=15 ——> 30+30=60
if x=4——> y=20 ——> 20+40=60
if x=2——> y=25 ——> 10+50=60
Answer: you would just do y= 4x (4•1 would be 4) plus 7. hope this helps!!
Step-by-step explanation: