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Stella [2.4K]
3 years ago
10

Solve for a 9a² = 16a College Intermediate Algebra

Mathematics
1 answer:
Fed [463]3 years ago
7 0

We want to solve 9a² = 16a for a.

Because the a is on both sides, a good strategy is to get all the a terms on one side and set it equal to zero. Then we apply the Zero Product Property (if the product is zero then so are its pieces and Factoring.

9a² = 16a

9a² - 16a = 0                <-----subtract 16a from both sides

a (9a - 16) = 0               <-----factor the common a on the left side

a = 0   OR   9a - 16 =0   <----apply Zero Product Property

Since a = 0 is already solved we work on the other equation.

9a - 16 = 0

9a = 16                        <----------- add 16 to both sides

a = 16/9                       <----------- divide both sides by 9


Thus a = 0 or a = 16/9

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3 years ago
Write an equation of the line with a slope of -3 and y-intercept of 0
klemol [59]

Answer:

y=-3x

Step-by-step explanation:

Slope intercept form is written as y=mx+b, where:

m= slope

b= y-intercept

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y=-3x+0

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y=-3x

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The angles in a triangle are represented by 5x, 8x, and 2x+9. What is the value of x?
Ahat [919]

Answer:

x = 11.4

Step-by-step explanation:

The sum of the angles of any triangle must add up to 180°.  Since we have the expressions for each angle:  5x, 8x, and (2x +9), we can solve for the variable of 'x' by adding the expressions together and setting them equal to 180:

5x + 8x + (2x +9) = 180

Combine like terms:  15x + 9 = 180

Use inverse operations: 15x + 9 - 9 = 180 - 9

                                                     15x = 171  or x = 11.4

Check:  5(11.4) + 8(11.4) + 2(11.4) + 9 = 57 + 91.2 + 22.8 + 9 = 180

8 0
3 years ago
Find DC (Image Below)
ioda

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3 years ago
A triangle has base 2x+1 and height 6x-3. What value of x would give an area of 240m2?
GREYUIT [131]

Answer:

The values of x which would give an area of 240m² would be:

x=-\frac{\sqrt{161}}{2},\:x=\frac{\sqrt{161}}{2}

Step-by-step explanation:

Given

The base of triangle b = 2x+1

The height of triangle h = 6x-3

The Area of the triangle A = 240 m²

The Area of the triangle has the formula

A = 1/2 × b × h

substituting b = 2x+1, h = 6x-3 and A = 240

240\:=\:\frac{1}{2}\:\left(2x+1\right)\:\times \left(6x-3\right)

480=\left(2x+1\right)\left(6x-3\right)

480=12x^2-3

Subtract 480 from both sides

12x^2-3-480=480-480

12x^2-483=0

3\left(4x^2-161\right)=0

3\left(2x+\sqrt{161}\right)\left(2x-\sqrt{161}\right)=0

Using the zero factor principle

if ab=0, then a=0 or b=0 (or both a=0 and b=0)

2x+\sqrt{161}=0\quad \mathrm{or}\quad \:2x-\sqrt{161}=0

solving

2x+\sqrt{161}=0

2x=-\sqrt{161}

Divide both sides by 2

\frac{2x}{2}=\frac{-\sqrt{161}}{2}

x=-\frac{\sqrt{161}}{2}

also solving

2x-\sqrt{161}=0

2x=\sqrt{161}

Divide both sides by 2

\frac{2x}{2}=\frac{\sqrt{161}}{2}

x=\frac{\sqrt{161}}{2}

Therefore, the values of x which would give an area of 240m² would be:

x=-\frac{\sqrt{161}}{2},\:x=\frac{\sqrt{161}}{2}

3 0
2 years ago
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