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Stella [2.4K]
3 years ago
10

Solve for a 9a² = 16a College Intermediate Algebra

Mathematics
1 answer:
Fed [463]3 years ago
7 0

We want to solve 9a² = 16a for a.

Because the a is on both sides, a good strategy is to get all the a terms on one side and set it equal to zero. Then we apply the Zero Product Property (if the product is zero then so are its pieces and Factoring.

9a² = 16a

9a² - 16a = 0                <-----subtract 16a from both sides

a (9a - 16) = 0               <-----factor the common a on the left side

a = 0   OR   9a - 16 =0   <----apply Zero Product Property

Since a = 0 is already solved we work on the other equation.

9a - 16 = 0

9a = 16                        <----------- add 16 to both sides

a = 16/9                       <----------- divide both sides by 9


Thus a = 0 or a = 16/9

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8 in the 10,000s place is worth 80,000.

8 in the hundreds place is worth 800.

80,000/800 = 100

Answer: 100 times.

6 0
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Answer:

In a simplified version it can be expressed as 3/4.

Hope that helped. x

Step-by-step explanation:

21 divided by 7 is 3

28 divided by 7 is 4.

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2 years ago
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Hi I need help on this!!
MA_775_DIABLO [31]

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8 0
2 years ago
The following stem-and-leaf plot represents the test scores for
rewona [7]

Considering the given stem-and-leaf plot, the quartiles are given as follows:

  • The first quartile is of 67.5.
  • The second quartile, which is the median, is of 84.5.
  • The third quartile is of 91.5.

<h3>What are the median and the quartiles of a data-set?</h3>

  • The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile.
  • The first quartile is the median of the first half of the data-set.
  • The third quartile is the median of the second half of the data-set.

There is an even number of elements(26), hence the median is the mean of the 13th and 14th elements, which are 83 and 86, hence:

Me = (83 + 86)/2 = 84.5.

The first half has 12 elements, hence the first quartile is the mean of the 6th and 7th elements, which are 67 and 68, hence:

Q1 = (67 + 68)/2 = 67.5.

The third half also has 12 elements, starting at the second 86, hence the third quartile is the mean of the 6th and 7th elements of this half, hence:

Q3 = (91 + 92)/2 = 91.5.

More can be learned about the quartiles of a data-set at brainly.com/question/28017610

#SPJ1

7 0
1 year ago
If two dice are rolled, find the probability of rolling two 6's.
djyliett [7]
Total no. of outcomes when two dice are rolled = 36

No. of outcome when 6 will be on both dice = 1

Probability of rolling two 6's = 1/36

Hope this helps!
8 0
3 years ago
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