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Stella [2.4K]
3 years ago
10

Solve for a 9a² = 16a College Intermediate Algebra

Mathematics
1 answer:
Fed [463]3 years ago
7 0

We want to solve 9a² = 16a for a.

Because the a is on both sides, a good strategy is to get all the a terms on one side and set it equal to zero. Then we apply the Zero Product Property (if the product is zero then so are its pieces and Factoring.

9a² = 16a

9a² - 16a = 0                <-----subtract 16a from both sides

a (9a - 16) = 0               <-----factor the common a on the left side

a = 0   OR   9a - 16 =0   <----apply Zero Product Property

Since a = 0 is already solved we work on the other equation.

9a - 16 = 0

9a = 16                        <----------- add 16 to both sides

a = 16/9                       <----------- divide both sides by 9


Thus a = 0 or a = 16/9

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The perimeter of a rectangle is equal to 163 yard. The width is 8 more than twice the length. Find the length and width.​
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Answer:

l = 29.4 yards

w = 66.8 yards

General Formulas and Concepts:

  • Order of Operations: BPEMDAS
  • Perimeter of a Rectangle: P = 2w + 2l

Step-by-step explanation:

<u>Step 1: Define</u>

P = 163 yards

w = 2l + 8

l = l

<u>Step 2: Set up equation</u>

P = 2w + 2l

163 = 2(2l + 8) + l

<u>Step 3: Solve for </u><em><u>l</u></em>

  1. Distribute 2:                              163 = 4l + 16 + l
  2. Combine like terms:                 163 = 5l + 16
  3. Subtract 16 on both sides:        147 = 5l
  4. Divide both sides by 5:             147/5 = l
  5. Rewrite:                                      l = 147/5
  6. Evaluate:                                    l = 29.4 yards

<u>Step 4: Find </u><em><u>w</u></em>

  1. Define:                    w = 2l + 8
  2. Substitute:              w = 2(29.4) + 8
  3. Multiply:                  w = 58.8 + 8
  4. Add:                        w = 66.8 yards
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