A because that is where they cross
The answer would be 6fg^3+5f^2g^2+f^3g-7
8(1-8p) + 8p
8 - 64p + 8p
8 - 56p
8 = 56p
1/7 = p
the assumption being that the first machine is the one on the left-hand-side and the second is the one on the right-hand-side.
the input goes to the 1st machine and the output of that goes to the 2nd machine.
a)
if she uses and input of 6 on the 2nd one, the result will be 6² - 6 = 30, if we feed that to the 1st one the result will be √( 30 - 5) = √25 = 5, so, simply having the machines swap places will work to get a final output of 5.
b)
clearly we can never get an output of -5 from a square root, however we can from the quadratic one, the 2nd machine/equation.
let's check something, we need a -5 on the 2nd, so

so if we use a "1" as the output on the first machine, we should be able to find out what input we need, let's do that.

so if we use an input of 6 on the first machine, we should be able to get a -5 as final output from the 2nd machine.

15. 12, 8, 14, 7, 16, 6, 18, .......,<br>b. 6, 20<br>a. 5, 18<br>d.6,21<br>C. 5, 20
babymother [125]
Answer:
What is the question. Please rewrite the question.