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Lyrx [107]
3 years ago
12

What’s 90% as a fraction in simplest form

Mathematics
1 answer:
larisa86 [58]3 years ago
4 0
90% = 90/100 which simplifies to 9/10
You might be interested in
Pls hurry
AlladinOne [14]

Step-by-step explanation:

To evaluate, substitute 29 for the variable in the expression.

To evaluate, substitute 31 for the variable in the equation.

To evaluate the expression, add 31 to 29.

The correct expression is n-31.

To evaluate the expression, subtract 31 from 29Pls hurry

Rafael writes an expression to represent "a number, n, decreased by thirty-one." Then he evaluates that expression if

n-29. Which statements are true about the expression and its evaluation? Check all that apply.

The correct expression is 31-n.

This is a subtraction expression.

This is an addition expression.

To evaluate, substitute 29 for the variable in the expression.

To evaluate, substitute 31 for the variable in the equation.

To evaluate the expression, add 31 to 29.

The correct expression is n-31.

To evaluate the expression, subtract 31 from 29..

4 0
3 years ago
Read 2 more answers
How many solutions does 10+5x=5x+10 have?
Arturiano [62]
Simplifying
10 + 5x = 5x + 10

Reorder the terms:
10 + 5x = 10 + 5x

Add '-10' to each side of the equation.
10 + -10 + 5x = 10 + -10 + 5x

Combine like terms: 10 + -10 = 0
0 + 5x = 10 + -10 + 5x
5x = 10 + -10 + 5x

Combine like terms: 10 + -10 = 0
5x = 0 + 5x
5x = 5x

Add '-5x' to each side of the equation.
5x + -5x = 5x + -5x

Combine like terms: 5x + -5x = 0
0 = 5x + -5x

Combine like terms: 5x + -5x = 0
0 = 0

Solving
0 = 0
Answer: 0 solutions
3 0
3 years ago
Find the sum 52,679 + 3,596
mojhsa [17]

Answer:

56,275

Step-by-step explanation:

6 0
3 years ago
Please help me on this and show me the steps to the answer.
Julli [10]
I guess you want to calculate the value of e. If so then:

-8.e = 4 . Divide both sides by 4:

-2.e = 1. Divide both sides by 2:
-e = 1/2. Multiply both sides with (-):

e = - 1/2


5 0
3 years ago
You randomly choose one of the morales.Without replacing the first marble, you choose a second marble. What is the probability o
IrinaK [193]
Let’s say, hypothetically speaking, you chose the second marble without replacing the first marble so, events are hypothetically dependent. Events are dependent if the occurrence of one hypothetical event hypothetically does affect the likelihood that the other events occur. The probably of two or more dependent events A and B is the probability of A times the probability of B after A hypothetically occurs

P(A and B) = P(A) x P(B after A)

Choose the first marble

The total number of hypothetical marbles are, hypothetically speaking, 4 on a hypothetical basis, and there is one red marble.

P(red)=1/4

Choose the second marble

Without hypothetically replacing the hypothetical first marble, you choose the hypothetical marble, hypothetically speaking. So, the total hypothetical number of marbles are, hypothetically, 3, and there is, hypothetically, one green marble.

P(green) = 1/3

The probability of choosing red and then, hypothetically, green is:

P(red and green) = P(red) x P(green)
=1/4 x 1/3

= 1/12

P(red and green) is hypothetically equal to 1/12 on a hypothetical account.

Final hypothetical answer: 1/12
4 0
2 years ago
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