3 years ago

13. which inequality has the following graphed solution?

Mathematics

1 answer:

mafiozo [28]3 years ago

5 0

B. You have to solve for X, and graph using whatever is less than or greater than. 4x + 12 < 4 to 4x < -8 to x < -2.

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3. In the television viewing data above, is there more than one way to

MAXImum [283]

Answer:

Yes because you could use due 7 + 8 to get 15 which is the easy way to blend with the 15 to get 30

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3 years ago

Determinați domeniul de definiție al funcției f:D→R, f(x)=(√2-3x)+2

Rudik [331]

Answer:

The domain is all real numbers less than or equal to two-third

Step-by-step explanation:

<u><em>The question in English is</em></u>

Determine the domain of the function f :D→R, $f(x)=\sqrt{2-3x}+2$

we know that

The radicand of the function must be greater than or equal to zero

$2-3x \geq 0$

Solve the inequality for x

subtract 2 both sides

$-3x \geq -2$

Multiply by -1 both sides

$3x \leq 2$

Divide by 3 both sides

$x \leq \frac{2}{3}$

The solution is the interval ----> (-∞,2/3]

therefore

The domain is all real numbers less than or equal to two-third

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3 years ago

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babunello [35]

The equivalent expression is $x^{16}y^{22}$

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3 years ago

Which of the following sequences of numbers are arithmetic sequences?

NNADVOKAT [17]

Either a or e that's all i can say

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3 years ago

Read 2 more answers

Identify the absolute extrema of the function and the x-values where they occur.

sladkih [1.3K]

$f(x)=6x+\dfrac{24}{x^2}+3\\
f'(x)=6-\dfrac{48}{x^3}\\
6-\dfrac{48}{x^3}=0\\
6x^3-48=0\\
6x^3=48\\
x^3=8\\
x=2\\
$

For $x$ the derivative is negative.
For $x>2$ the derivative is positive.
Therefore at $x=2$ there's a minimum.

$f_{min}=6\cdot2+\dfrac{24}{2^2}+3=12+6+3=21$

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3 years ago