Answer:
See below for the matrix
D = 100
Step-by-step explanation:
![\left[\begin{array}{cccc}3&2&1&-8\\-1&-2&4&7\\1&-6&-3&15\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D3%262%261%26-8%5C%5C-1%26-2%264%267%5C%5C1%26-6%26-3%2615%5Cend%7Barray%7D%5Cright%5D)
3 2 1
D = -1 -2 4 = 3(-2)(-3) + 2(4)(1) + 1(-1)(-6)
1 -6 -3
- 1(-2)(1) - 3(4)(-6) - 2(-1)(-3)
= 18 + 8 + 6 + 2 + 72 - 6
= 100
Sorry, I can't type the vertical bars.
I hope this is what you are looking for.
Answer:
y=-3x-12
Step-by-step explanation:
Plug into equation y=mx+b
3=(-3)-5+b
Simplify
3=15+b
Subtract 15 from both sides
-12=b
Add slope and y-intercept into base equation
y=-3x-12
Answer:
0
Step-by-step explanation:
125×^6_81=0
×^6 we do not support this expression
ans = 0
The point that best represents 1/3 is point M .
The number line ranges from 0 to 0.5 with 10 divi
I started by labeling the right angle (Angle C) 90º. Next, I wrote down everything in one equation.
2x + 90 + 3x - 20 = 180º (180 degrees in a triangle)
Next, I add 20 on both sides.
2x + 90 + 3x = 200º
I combine like terms (2x and 3x)
5x + 90 = 200º
I subtract 90 from both sides.
5x = 110º
Divide 110 by 5 to get x.
x = 22
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For problem two, I label all the angles I know.
49º + 80º + r = 180º
I add 80 and 49.
129º + r = 180º
I subtract 180 and 129 and get 51º, which is your angle for R.
For angle X, you know that angle R plus angle X equals half of a circle, which is 180º
We know from before that 129º is 180º without R, so X is 129º
I hope this helps! Let me know if I'm wrong!
